在 category.php 页面中，我按 sub-categries 列出帖子，哪个子类别包含3个以上的帖子，我将显示 VIEW ALL 按钮转到 view-all.php 页面 . 在我的wordpress themes文件夹中，我有一个名为“ view-all.php ”的页面，用于查看特定子类别下的所有帖子 . 但是我不明白如何用一些 parameter 将那个VIEW ALL按钮链接到 view-all.php 页面 . 请帮我提一下你的建议，因为我是wordpress的初学者谢谢
这是 category.php
<?php get_header(); ?>
<?php get_sidebar(); ?>
<div class="col-lg-9 col-md-9 col-sm-9 col-xs-12">
<?php
// get category ID of particular category
$current_category = single_cat_title("", false);
$category_id = get_cat_ID($current_category);
// end getting category ID
// Get the name of sub-category
$categories = get_categories('child_of='.$category_id);
foreach ($categories as $category) {
// Display the sub category information using $category values like $category->cat_name
echo "<div class='sub-category-wrapper'>";
echo '<h3 class="sub-cat-name">» '.$category->name.'</h3>';
// get number of posts under this sub-category
$total_posts = $category->count;
// Make a loop to display post link which are in this sub category
foreach (get_posts( array(
'category' => $category->term_id,
'orderby' => 'date',
'order' => 'DESC',
'numberposts' => 3, // limit number of posts
) ) as $post) {
setup_postdata( $post );
echo "<div class='col-lg-4 col-md-4 col-sm-4 col-xs-12 post-link'>";
echo '<h4 class="title"><a href="'.get_permalink($post->ID).'">'.get_the_title().'</a></h4>';
echo '<div class="post-thumb">';
echo '<a href="'.get_permalink($post->ID).'">';
if ( has_post_thumbnail() ) {
the_post_thumbnail();
}
echo '</a>';
echo '</div>';
echo "</div>";
}
if( $total_posts > 3 )
{ ?>
<a href="#">View all</a>
<?php }
echo "</div>"; /* sub-category-wrapper */
}
?>
</div>
<?php get_footer(); ?>
1 回答
如果它们位于一个目录中，只需在上面的代码中更改此行