由于安全问题，无法在iOS中打开HTTP链接-Java 学习之路

The solution to the problem but still getting the error

App Transport Security已阻止明文HTTP（http：//）资源加载，因为它不安全 . 可以通过应用程序的Info.plist文件配置临时例外 .

我已经在图片上尝试了解决方案，但仍然收到错误

import UIKit

   class ViewController: UIViewController {


   lazy var data = NSMutableData()


    override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.



    let url = NSURL(string: "http://android.goidx.com/search")
    let session = NSURLSession.sharedSession()
    let task = session.dataTaskWithURL(url!, completionHandler: { (data, response, error) -> Void in
        if error != nil {
            print(error)
            } else {
            do {
                let jsonResult = try NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions.MutableContainers) as!  NSDictionary
                // print(jsonResult)

                print(jsonResult[0])
            } catch {
                print("my error")
            }
        }

    })

    task.resume()





}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
  }




 }

1 回答

您的plist文件应如下所示：
enter image description here
并注意您的代码崩溃了应用程序，因为您正在转换为应该是数组的字典：

override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.



        let url = NSURL(string: "http://android.goidx.com/search")
        let session = NSURLSession.sharedSession()
        let task = session.dataTaskWithURL(url!, completionHandler: { (data, response, error) -> Void in
            if error != nil {
                print(error)
            } else {
                do {
                    let jsonResult = try NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions.MutableContainers) as!  NSArray
                    // print(jsonResult)

                    print(jsonResult[0])
                } catch {
                    print("my error")
                }
            }

        })

        task.resume()





    }

一切都应该工作 - 它对我有用 .

回复于 2024-05-14T03:16:05+08:00

由于安全问题，无法在iOS中打开HTTP链接

1 回答

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