C程序读取大文本文件并在struct中存储信息

1 回答

• 0

  您只需要进行一些检查即可获得结果 . 您需要保留以前的名称，直到找到仅为“\ n”的行 . 也无需重新定义C标准库中已存在的函数（但如果需要，可以重新实现它们）：

  #include <stdio.h>
  #include <stdlib.h>
  #include <string.h>
  #define SIZE 100
  #define START 0
  #define END 374
  
  //a structure to represent an actor
  
  struct Actor{
      char lastName[20];
      char firstName[20];
      char movie[50];
  };
  
  //method to print name and movie of an actor in separate lines
  
  void print(struct Actor actor) {
      printf("First name: %s\n",actor.firstName);
      printf("Last name: %s\n",actor.lastName);
      printf("Movie: %s\n\n",actor.movie);
  }
  
  int main(){
  
      //creating a file pointer, asking user for the file name
      FILE *fp;
      //opening file in read mode
      fp = fopen("./actors.txt","r");
  
      if(fp == NULL){
          //file can not be opened
          printf("File not found!\n");
          return 0;
      }
  
      //creating a char array to store each line, one at a time
      char buffer[100];
      //creating an Actor structure object
      struct Actor actor;
      //reading all lines one by one
      int i = 0;
      int check=0;
      char *ptr;
      while(fgets(buffer, 100, fp)){
          i++;
          int len;
          if(i > START && i < END ){
              if ( strcmp( buffer, "\n") == 0)
              {
                  check = 0;
                  continue;
              }
              if( !check)
              {
                  len = strchr(buffer, ',') - buffer - 1;
                  strncpy( actor.lastName, buffer, len);
                  actor.lastName[len] = '\0';
                  if( (ptr = strchr(buffer, ',')))
                  {
                      len = strchr(buffer, '\t') - ptr -1;
                      strncpy( actor.firstName, ptr+1, len);
                      actor.firstName[len] = '\0';
                  }
                  check = 1;
              }
              if( (ptr = strchr(buffer, '\t')))
              {
                  len = strchr( ptr, '(') - ptr-2;
                  strncpy( actor.movie, ptr+2, len);
                  actor.movie[len] = '\0';
              }
              //printing actor
              print(actor);
          }
      }
          //closing file
      fclose(fp);
  }
  

  产量

  First name:  Brian (I)
  Last name: Par
  Movie: Blue Ice 
  
  First name:  Brian (I)
  Last name: Par
  Movie: Eskimo Day 
  
  First name:  Brian (I)
  Last name: Par
  Movie: Summer in the Suburbs 
  
  First name:  Brian (I)
  Last name: Par
  Movie: The fairy queen 
  
  First name:  Marcus (II)
  Last name: Roger
  Movie: .357 
  
  First name:  Marcus (II)
  Last name: Roger
  Movie: Streets 
  
  First name:  Marcus (II)
  Last name: Roger
  Movie: Summer in the Suburbs 
  
  First name:  Marcus (II)
  Last name: Roger
  Movie: "15 Storeys High"
  

  如果你想要你也可以通过创建一个像这样的函数来概括它

  void parse( char * dest, char * string, char delim, int offset1, int offset2)
  {
      int len = strchr(string, delim) - string - 1 - offset1;
      strncpy( dest, string + 1 + offset2, len);
      dest[len] = '\0';
  }
  

  这将使代码看起来像这样：

  if( !check)
          {
              parse(actor.lastName, buffer, ',', 0, -1);
              if( (ptr = strchr(buffer, ',')))
                  parse( actor.firstName, ptr, '\t', 0,0);
              check = 1;
          }
          if( (ptr = strchr(buffer, '\t')))
              parse( actor.movie, ptr, '(', 1, 1);
          //printing actor
          print(actor);
  

  回复于 2024-04-28T22:09:28+08:00