static class DataGridHelper
{
static public DataGridCell GetCell(DataGrid dg, int row, int column)
{
DataGridRow rowContainer = GetRow(dg, row);
if (rowContainer != null)
{
DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(rowContainer);
// try to get the cell but it may possibly be virtualized
DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
if (cell == null)
{
// now try to bring into view and retreive the cell
dg.ScrollIntoView(rowContainer, dg.Columns[column]);
cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
}
return cell;
}
return null;
}
static public DataGridRow GetRow(DataGrid dg, int index)
{
DataGridRow row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(index);
if (row == null)
{
// may be virtualized, bring into view and try again
dg.ScrollIntoView(dg.Items[index]);
row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(index);
}
return row;
}
static T GetVisualChild<T>(Visual parent) where T : Visual
{
T child = default(T);
int numVisuals = VisualTreeHelper.GetChildrenCount(parent);
for (int i = 0; i < numVisuals; i++)
{
Visual v = (Visual)VisualTreeHelper.GetChild(parent, i);
child = v as T;
if (child == null)
{
child = GetVisualChild<T>(v);
}
if (child != null)
{
break;
}
}
return child;
}
}
1 回答
你应该通过
Style
/Trigger
或Binding
用这样的转换器这样做默认情况下,
DataGrid
正在使用虚拟化,因此只会加载此时用户可见的DataGridRows
. 其他行将在可见后创建,因此如果您尝试在后面的代码中设置一些单元格可能会变得非常混乱(您尝试访问的单元格可能尚不存在 . )要在索引行/列获取
DataGridCell
,您可以定义一个帮助程序类(DataGridHelper
)并像这样使用它DataGridHelper