inlineformset_factory在创建后创建新对象并编辑对象-Java 学习之路

在django文档中，有一个使用inlineformset_factory来编辑已创建对象的示例

https://docs.djangoproject.com/en/dev/topics/forms/modelforms/#using-an-inline-formset-in-a-view

我改变了这个例子：

def manage_books(request):
    author = Author()
    BookInlineFormSet = inlineformset_factory(Author, Book, fields=('title',))
    if request.method == "POST":
        formset = BookInlineFormSet(request.POST, request.FILES, instance=author)
        if formset.is_valid():
            formset.save()
            return HttpResponseRedirect(author.get_absolute_url())
    else:
        formset = BookInlineFormSet(instance=author)
    return render_to_response("manage_books.html", {
        "formset": formset,
    })

使用上面的内容，它只渲染没有父模型的内联模型 .

使用inlineformset_factory创建一个新对象，比如作者，与多个图书相关联，这是什么方法？

使用django docs上面的Author Book模型的示例将很有帮助 . django docs仅提供了如何使用inlineformset_factory编辑已创建对象但未创建新对象的示例

4 回答

我一开始没有正确地阅读你的问题 . 您还需要呈现父模型的表单 . 我没有对此进行过测试，我已经完成了之前我所做过的事情以及之前关联的答案，但它应该可行 .

UPDATE

如果您同时使用视图并进行编辑，则应首先检查作者ID . 如果没有ID，它会将两个表单呈现为一个新实例，而使用ID它将用现有数据填充它们 . 然后你可以检查是否有POST请求 .

def manage_books(request, id):

    if id:
        author = Author.objects.get(pk=author_id)  # if this is an edit form, replace the author instance with the existing one
    else: 
        author = Author()
    author_form = AuthorModelForm(instance=author) # setup a form for the parent

    BookInlineFormSet = inlineformset_factory(Author, Book, fields=('title',))
    formset = BookInlineFormSet(instance=author)

    if request.method == "POST":
        author_form = AuthorModelForm(request.POST)

        if id: 
            author_form = AuthorModelForm(request.POST, instance=author)

        formset = BookInlineFormSet(request.POST, request.FILES)

        if author_form.is_valid():
            created_author = author_form.save(commit=False)
            formset = BookInlineFormSet(request.POST, request.FILES, instance=created_author)

            if formset.is_valid():
                created_author.save()
                formset.save()
                return HttpResponseRedirect(created_author.get_absolute_url())

    return render_to_response("manage_books.html", {
        "author_form": author_form,
        "formset": formset,
    })

回复于 2024-05-09T17:19:55+08:00

我已经使用Django基于类的视图完成了这项工作 .

这是我的方法：

models.py

from django.db import models

class Author(models.Model):
    name = models.CharField(max_length=100)


class Book(models.Model):
    author = models.ForeignKey(Author)
    title = models.CharField(max_length=100)

forms.py

from django.forms import ModelForm
from django.forms.models import inlineformset_factory

from crispy_forms.helper import FormHelper
from crispy_forms.layout import Layout, Fieldset

from .models import Author, Book

class AuthorForm(ModelForm):
    class Meta:
        model = Author
        fields = ('name', )

    @property
    def helper(self):
        helper = FormHelper()
        helper.form_tag = False # This is crucial.

        helper.layout = Layout(
            Fieldset('Create new author', 'name'),
        )

        return helper


class BookFormHelper(FormHelper):
    def __init__(self, *args, **kwargs):
        super(BookFormHelper, self).__init__(*args, **kwargs)
        self.form_tag = False
        self.layout = Layout(
            Fieldset("Add author's book", 'title'),
        )


BookFormset = inlineformset_factory(
    Author,
    Book,
    fields=('title', ),
    extra=2,
    can_delete=False,
)

views.py

from django.views.generic import CreateView
from django.http import HttpResponseRedirect

from .forms import AuthorForm, BookFormset, BookFormHelper
from .models import Book, Author

class AuthorCreateView(CreateView):
    form_class = AuthorForm
    template_name = 'library/manage_books.html'
    model = Author
    success_url = '/'

    def get(self, request, *args, **kwargs):
        self.object = None
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        book_form = BookFormset()
        book_formhelper = BookFormHelper()

        return self.render_to_response(
            self.get_context_data(form=form, book_form=book_form)
        )

    def post(self, request, *args, **kwargs):
        self.object = None
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        book_form = BookFormset(self.request.POST)

        if (form.is_valid() and book_form.is_valid()):
            return self.form_valid(form, book_form)

        return self.form_invalid(form, book_form)

    def form_valid(self, form, book_form):
        """
        Called if all forms are valid. Creates a Author instance along
        with associated books and then redirects to a success page.
        """
        self.object = form.save()
        book_form.instance = self.object
        book_form.save()

        return HttpResponseRedirect(self.get_success_url())

    def form_invalid(self, form, book_form):
        """
        Called if whether a form is invalid. Re-renders the context
        data with the data-filled forms and errors.
        """
        return self.render_to_response(
            self.get_context_data(form=form, book_form=book_form)
        )

    def get_context_data(self, **kwargs):
        """ Add formset and formhelper to the context_data. """
        ctx = super(AuthorCreateView, self).get_context_data(**kwargs)
        book_formhelper = BookFormHelper()

        if self.request.POST:
            ctx['form'] = AuthorForm(self.request.POST)
            ctx['book_form'] = BookFormset(self.request.POST)
            ctx['book_formhelper'] = book_formhelper
        else:
            ctx['form'] = AuthorForm()
            ctx['book_form'] = BookFormset()
            ctx['book_formhelper'] = book_formhelper

        return ctx

urls.py

from django.conf.urls import patterns, url
from django.views.generic import TemplateView

from library.views import AuthorCreateView

urlpatterns = patterns('',
    url(r'^author/manage$', AuthorCreateView.as_view(), name='handle-books'),
    url(r'^$', TemplateView.as_view(template_name='home.html'), name='home'),
)

manage_books.html

{% load crispy_forms_tags %}

<head>
  <!-- Latest compiled and minified CSS -->
  <link rel="stylesheet"
    href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.4/css/bootstrap.min.css">
</head>

<div class='container'>
  <form method='post'>
    {% crispy form %}
    {{ book_form.management_form }}
    {{ book_form.non_form_errors }}

    {% crispy book_form book_formhelper %}
    <input class='btn btn-primary' type='submit' value='Save'>
  </form>
<div>

Notice:

这是一个使用 inlineformset_factory 功能和Django通用基于类的视图的简单可运行示例
我正在安装 django-crispy-forms 已安装，并且已正确配置 .
代码存储库托管在：https://bitbucket.org/slackmart/library_example

我知道显示解决方案的代码更多，但是开始使用Django基于类的视图非常棒 .

回复于 2024-05-09T17:19:55+08:00

根据Onyeka提供的广泛助手，我发布了我的最终解决方案 .

下面我使用Django Docs中的Author和Book示例发布使用Django的inlineformset_factory的Add和Edit解决方案 .

首先，添加作者对象，附加3个额外的Book对象 .

显然，这进入你的 views.py

def add_author(request):
    '''This function creates a brand new Author object with related Book objects using inlineformset_factory'''
    author = Author()
    author_form = AuthorModelForm(instance=author) # setup a form for the parent
BookInlineFormSet = inlineformset_factory(Author, Book, fields=('title',))

if request.method == "POST":
    author_form = AuthorModelForm(request.POST)
    formset = BookInlineFormSet(request.POST, request.FILES)

    if author_form.is_valid():
        created_author = author_form.save(commit=False)
        formset = BookInlineFormSet(request.POST, request.FILES, instance=created_author)

        if formset.is_valid():
            created_author.save()
            formset.save()
            return HttpResponseRedirect(created_author.get_absolute_url())
else:
    author_form = AuthorModelForm(instance=author)
    formset = BookInlineFormSet()

return render(request, "add_author.html", {
    "author_form": author_form,
    "formset": formset,
})


def edit_author(request, author_id):
    '''This function edits an Author object and its related Book objects using inlineformset_factory'''
    if id:
        author = Author.objects.get(pk=author_id)  # if this is an edit form, replace the author instance with the existing one
    else:
        author = Author()
    author_form = AuthorModelForm(instance=author) # setup a form for the parent
BookInlineFormSet = inlineformset_factory(Author, Book, fields=('title',))
formset = BookInlineFormSet(instance=author)

if request.method == "POST":
    author_form = AuthorModelForm(request.POST)

    if id:
        author_form = AuthorModelForm(request.POST, instance=author)

    formset = BookInlineFormSet(request.POST, request.FILES)

    if author_form.is_valid():
        created_author = author_form.save(commit=False)
        formset = BookInlineFormSet(request.POST, request.FILES, instance=created_author)

        if formset.is_valid():
            created_author.save()
            formset.save()
            return HttpResponseRedirect(created_author.get_absolute_url())

return render(request, "edit_author.html", {
    "author_id": author_id, # This author_id is referenced 
                            # in template for constructing the posting url via {% url %} tag
    "author_form": author_form,
    "formset": formset,
})

这部分进入你的 urls.py ，假设已导入视图，并且已经构造了urlpatterns .

...
    url(r'^add/book/$', views.add_author, name='add_author'),
    url(r'^edit/(?P<author_id>[\d]+)$', views.edit_author, name='edit_author'),
...

现在到模板部分 . 编辑作者对象模板（edit_author.html）看起来像这样（没有应用样式）

<form action="{% url 'edit_book' author_id %}" method="POST" >
<!-- See above: We're using the author_id that was passed to template via views render of the edit_author(...) function -->
{% csrf_token %} <!-- You're dealing with forms. csrf_token must come -->
{{ author_form.as_p }}
{{ formset.as_p }}
<input type="submit" value="submit">
</form>

要通过模板添加全新的作者对象（add_author.html）：

<form action="." method="POST" >{% csrf_token %}
{{ author_form.as_p }}
{{ formset.as_p }}
<input type="submit" value="submit">
</form>

注意：

使用action =' . '似乎是一种构建url的廉价方式，因此表单将表单数据发布到同一页面 . 在这个例子中，使用action =' . '对于edit_author.html模板，始终将表单发布到/ edit /而不是/ edit / 1或/ edit / 2

使用{％url 'edit_author' author_id％}构建网址可确保将表单 always 发布到正确的网址 . 没有使用{％url％}会花费我很多时间和麻烦 .

非常感谢Onyeka .

回复于 2024-05-09T17:19:55+08:00

8

我做了你正在尝试的事情：https://github.com/yakoub/django_training/tree/master/article

您需要使用prefix属性创建单独的表单 . 然后当你保存时，你需要遍历所有书籍并将它们与你刚创建的作者联系起来 .

回复于 2024-05-09T17:19:55+08:00

inlineformset_factory在创建后创建新对象并编辑对象

4 回答

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