当“noImplicitAny”:false时,我的代码工作正常 .
import ...;
@Injectable()
export class HeroService {
private _cachedHeroes: Observable<Hero[]>;
private _init: boolean;
private _heroesObserver: Observer<Hero[]>;
private _heroObserver: Observer<Hero>;
heroes$: Observable<Hero[]>;
hero$: Observable<Hero>;
public _dataStore: { heroes: Hero[], hero: Hero };
constructor (private http: Http) {
this._init = true;
this._dataStore = { heroes: [], hero: {_id: null, name: null} };
this.heroes$ = new Observable((observer: any) => this._heroesObserver = observer).share();//.publishReplay(1).refCount();
this.hero$ = new Observable((observer: any) => this._heroObserver = observer).share();
this._baseUrl = 'http://localhost:8081/api/hero/';
}
loadHero1(id: number) {
this.hero$ = this._cachedHeroes.map(heroes => heroes.find(hero => {hero._id === id;}))
.catch(handleError)
.subscribe( data => {
this._dataStore.hero = data;
this._heroObserver.next(this._dataStore.hero);
},
error => handleError('Could not load hero.')
);
}
.......
}
由于我想使其类型安全,我将tsconfig.json更改为“noImplicitAny”:true .
然后我收到以下错误
[0] services/hero.service.ts(58,7): error TS2322: Type 'Subscription' is not assignable to type 'Observable<Hero>'.
[0] Property '_isScalar' is missing in type 'Subscription'.
[1] [BS] File changed: dist\services\hero.js
[1] [BS] File changed: dist\services\common.js
[0] services/hero.service.ts(58,65): error TS2345: Argument of type '(hero: Hero) => void' is not assignable to parameter of type '(value: Hero, index: number, obj: Hero[]) => boolean'.
[0] Type 'void' is not assignable to type 'boolean'.
这是我的问题
-
如何从订阅类型转换this._cachedHeroes.map() . subscribe()到类型Observable以解决TS2322错误?我试过
<Observable<Hero[]>>.this._cachedHeroes....
但是没用 . -
如何定义TypeScript箭头函数的参数类型以解决TS2345错误?我试过
heroes.find( (hero: Hero) => {hero._id === id;})
但它没有用 . -
如何在以下代码中将显式any更改为Observer类型?
this.hero $ = new Observable((observer:any)=> this._heroObserver = observer).share();
任何建议表示赞赏 .
2 回答
在@GünterZöchbauer的帮助下,我把这件事理顺了 . 因此添加return语句将解决类型不匹配问题 . 这是通过编译器检查的修改代码 .
subscribe()
返回Subscription
,而不是Observable
如果您将
subscribe()
更改为map()
,它应该可以正常工作或者改变
至
但我不认为这不是你的代码的意图 .