在Safari中打开链接而不是UIWebVIew？

7 回答

• 1

  您是否已将 UIWebView 的代表设置为 UIViewController ？ 's nothing obviously wrong with your code as far as I can see, so it'可能是那么小的东西 .

  回复于 2024-04-28T11:34:05+08:00
• 0

  在课堂上添加..

  @interface yourViewController : UIViewController
  <UIWebViewDelegate>
  

  在View did load中添加它

  - (void)viewDidLoad
  {
      [description loadHTMLString:string baseURL:nil];
          description.delegate = self;
  }
  

  在.m文件中添加此项

  -(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
      if ( inType == UIWebViewNavigationTypeLinkClicked ) {
          [[UIApplication sharedApplication] openURL:[inRequest URL]];
          return NO;
      }
  
      return YES;
  }
  

  注意：

  UIWebView *description;
  @synthesize description;
  

  然后它将完美地以你应得的方式工作.. !! :)

  回复于 2024-04-28T11:34:05+08:00
• -3

  在此之后使用此UIWebview方法将UIWebView的 delegate 设置为 UIViewController 并检查条件，例如现在webview当前url是google.com，如果假设您单击了gmail，则url包含带有gmail的字符串 . 使用下面的方法打开一个safari浏览器并自动加载该url .

  -(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
      if ( inType == UIWebViewNavigationTypeLinkClicked ) {
          NSURL *url = [inRequest URL];
          if ([[url absoluteString] rangeOfString:@"gmail"].location == NSNotFound) {
              [[UIApplication sharedApplication] openURL:[inRequest URL]];
              return NO;
          }
      }
      return YES;
  }
  

  回复于 2024-04-28T11:34:05+08:00
• 23

  如果你已经正确设置了UIWebViewDelegate，那就干脆做了

  self.webView loadHTMLString:_string baseURL:nil
  self.webView.delegate = self;
  

  应该管用

  回复于 2024-04-28T11:34:05+08:00
• 21

  添加此行（self.webview.delegate = self;）

  例如viewController.m中的示例

  NSString *htmlFile = [[NSBundle mainBundle] pathForResource:@"index" ofType:@"html"];
  NSString* htmlString = [NSString stringWithContentsOfFile:htmlFile encoding:NSUTF8StringEncoding error:nil];
  [self.webview loadHTMLString:htmlString baseURL:nil];
  self.webview.delegate = self;
  

  回复于 2024-04-28T11:34:05+08:00
• 0

  Apple在iOS 9上引入了Safari View Controller.Safari View Controller将用户期望从Safari获得的所有功能带到您的应用程序，而无需离开它 .

  首先，我们需要导入Safari服务

  #import <SafariServices/SafariServices.h>
  

  对于目标C： -

  NSString *yourUrl = @"http://yourURL";
  SFSafariViewController *svc= [[SFSafariViewController alloc] initWithURL:[NSURL URLWithString: yourUrl]];
  [self presentViewController:svc animated:YES completion:nil];
  

  对于斯威夫特： -

  let svc = SFSafariViewController(URL: NSURL(string: self.urlString)!)
  self.presentViewController(svc, animated: true, completion: nil)
  

  回复于 2024-04-28T11:34:05+08:00
• 0

  是的，在你的超链接标签中添加

  target="blank"
  

  一个问号就可以了，谢谢

  回复于 2024-04-28T11:34:05+08:00