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使用web.xml配置嵌入式jetty?

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我试图用我的Web应用程序生成一个战争以及一个带有嵌入式jetty的自包含jar文件 . 对于嵌入式jetty(jar文件分发),我添加一个servlet,如下所示:

public static void main(String[] args) throws Exception {
    Server server = new Server(8080);

    ServletContextHandler context = new ServletContextHandler(ServletContextHandler.SESSIONS);
    context.setContextPath("/");
    server.setHandler(context);

    context.addServlet(new ServletHolder(new HelloServlet()),"/*");

    server.start();
    server.join();
}

war文件分发使用web.xml文件,该文件在web-app部分中包含以下内容:

<servlet>
    <servlet-class>com.example.HelloServlet</servlet-class>
    <servlet-name>SimplestServer</servlet-name>
</servlet>
<servlet-mapping>
    <servlet-name>HelloServlet</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

这有效 . 但是,我想摆脱两种方法之间的重复 . 即,当我添加一个新的servlet时,我想要只在一个位置配置它 . 我可以从嵌入式jetty加载和使用web.xml文件吗?

2 回答

  • 17

    使用org.eclipse.jetty.webapp.WebAppContext

    例:

    package jetty;
    
    import org.eclipse.jetty.server.Server;
    import org.eclipse.jetty.webapp.WebAppContext;
    
    public class OnWebApp
    {
        public static void main(String[] args) throws Exception
        {
            // Create a basic jetty server object that will listen on port 8080.
            // Note that if you set this to port 0 then a randomly available port
            // will be assigned that you can either look in the logs for the port,
            // or programmatically obtain it for use in test cases.
            Server server = new Server(8080);
    
            // The WebAppContext is the entity that controls the environment in
            // which a web application lives and breathes. In this example the
            // context path is being set to "/" so it is suitable for serving
            // root context requests and then we see it setting the location of
            // the war. A whole host of other configurations are available,
            // ranging from configuring to support annotation scanning in the
            // webapp (through PlusConfiguration) to choosing where the webapp
            // will unpack itself.
            WebAppContext webapp = new WebAppContext();
            webapp.setContextPath("/");
            webapp.setWar("path/to/my/test.war");
    
            // A WebAppContext is a ContextHandler as well so it needs to be set to
            // the server so it is aware of where to send the appropriate requests.
            server.setHandler(webapp);
    
            // Start things up! By using the server.join() the server thread will
            // join with the current thread.
            // See http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/Thread.html#join()
            // for more details.
            server.start();
            server.join();
        }
    }
    

    请注意,您将构建一个普通的WAR文件,并将其与Jetty一起使用 .

    如果您有特殊要求,例如Annotation扫描或JNDI,那么您需要进入配置规范 .

    // Enable parsing of jndi-related parts of web.xml and jetty-env.xml
    org.eclipse.jetty.webapp.Configuration.ClassList classlist =
       org.eclipse.jetty.webapp.Configuration.ClassList.setServerDefault(server);
    
    // Enable JNDI
    classlist.addAfter("org.eclipse.jetty.webapp.FragmentConfiguration",
       "org.eclipse.jetty.plus.webapp.EnvConfiguration",
       "org.eclipse.jetty.plus.webapp.PlusConfiguration");
    
    // Enable Annotation Scanning
    classlist.addBefore("org.eclipse.jetty.webapp.JettyWebXmlConfiguration",
      "org.eclipse.jetty.annotations.AnnotationConfiguration");
    

    有关WebAppContext中较长的示例,请参阅ServerWithAnnotations示例 .

    另请注意,您将使用此技术制定所有webapp类加载器规则 . 这意味着您将拥有webapp的类加载器和服务器的另一个类加载器 . 这一点很重要 .

    您可以对WebAppContext进行类加载器的一些调整,但是您无法消除它们,只是控制它们的行为方式 .

    WebAppContext webapp = new WebAppContext();
    // ... various setup of the webapp ...
    // Flip the classloader priority from servlet spec where webapp is first to
    // Standard java behavior of parent (aka Server classloader) is first.
    webapp.setParentLoaderPriority(true);
    

    也可以看看:

  • 17

    我最终使用了Joakim的方法,但指向webapp目录而不是war文件 .

    public static void main(String[] args) throws Exception {
        Server server = new Server(8080);
    
        String rootPath = SimplestServer.class.getClassLoader().getResource(".").toString();
        WebAppContext webapp = new WebAppContext(rootPath + "../../src/main/webapp", "");
        server.setHandler(webapp);
    
        server.start();
        server.join();
    }
    

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