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带有美元和季度的收银机以C输出

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我必须设置一个收银机，其中有一个用户输入要支付的金额，它必须输出要支付的金额，然后输出支付金额所需的贷款数量，然后是支付金额所需的季度数量等等......我已经设法支付了要支付的金额以及截断支付金额所需的套数，但我不知道如何解决季度，硬币的数量，镍和便士需要支付 . 这是我的代码：

#include <stdio.h>
#include <math.h>

int main (void)

{
        double cost;
        int loonies, quarters;
        float loonreq;


        printf ("Please enter the amount to be paid: ");
        scanf ("%lf", &cost);

        printf ("Change Due: $ %.2f\n", cost);

        loonies = cost;
        printf ("Loonies required: %d, ", loonies);

        loonreq = cost - loonies;
        printf ("balance owing: $ %.2f\n", loonreq);

        return 0;
}
c if-statement

1 回答

  • 1

    干得好！

    #include <stdio.h>
#include <math.h>

int main (void)

{
    double cost;
    int loonies, quarters, dimes, nickels, pennies;
    float loonreq;
    float balance;


    printf ("Please enter the amount to be paid: ");
    scanf ("%lf", &cost);

    printf ("Change Due: $ %.2f\n", cost);

    loonies = cost;
    printf ("Loonies required: %d, ", loonies);

    loonreq = cost - loonies;
    printf ("balance owing: $ %.2f\n", loonreq);

    quarters = (int)(((int)(100*loonreq))/25);
    printf("num quarters: %d \n",quarters);
    balance = loonreq - (quarters*.25);
    printf("balance owing: %.2f$ \n", balance);
    dimes = (int)(((int)(100*balance))/10);
    balance = balance - (dimes*.1);
    printf("num dimes: %d \n", dimes);
    printf("balance owing: %.2f$ \n", balance);

    nickels = (int)(((int)(100*balance))/5);
    printf("num nickels: %d \n", nickels);
    balance = balance - (nickels*.05);
    pennies = (int)(balance*100);
    printf("balance owing: %.2f$ \n", balance);
    printf("num pennies: %d \n", pennies);


    return 0;
}
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