Dim lastRow as long
Range("A1").select
lastRow = Cells.Find("*",SearchOrder:=xlByRows,SearchDirection:=xlPrevious).Row
使用示例：
cells(lastRow,1)="Ultima Linha, Last Row. Youpi!!!!"
'or
Range("A" & lastRow).Value = "FIM, THE END"
21
function LastRowIndex(byval w as worksheet, byval col as variant) as long
dim r as range
set r = application.intersect(w.usedrange, w.columns(col))
if not r is nothing then
set r = r.cells(r.cells.count)
if isempty(r.value) then
LastRowIndex = r.end(xlup).row
else
LastRowIndex = r.row
end if
end if
end function
' Returns the 1-based row number of the last row having a non-empty value in the given column (0 if the whole column is empty)
Private Function getLastNonblankRowInColumn(ws As Worksheet, colNo As Integer) As Long
' Force Excel to recalculate the "last cell" (the one you land on after CTRL+END) / "used range"
' and get the index of the row containing the "last cell". This is reasonably fast (~1 ms/10000 rows of a used range)
Dim lastRow As Long: lastRow = ws.UsedRange.Rows(ws.UsedRange.Rows.Count).Row - 1 ' 0-based
' Since the "last cell" is not necessarily the one we're looking for (it may be in a different column, have some
' formatting applied but no value, etc), we loop backward from the last row towards the top of the sheet).
Dim wholeRng As Range: Set wholeRng = ws.Columns(colNo)
' Since accessing cells one by one is slower than reading a block of cells into a VBA array and looping through the array,
' we process in chunks of increasing size, starting with 1 cell and doubling the size on each iteration, until MAX_CHUNK_SIZE is reached.
' In pathological cases where Excel thinks all the ~1M rows are in the used range, this will take around 100ms.
' Yet in a normal case where one of the few last rows contains the cell we're looking for, we don't read too many cells.
Const MAX_CHUNK_SIZE = 2 ^ 10 ' (using large chunks gives no performance advantage, but uses more memory)
Dim chunkSize As Long: chunkSize = 1
Dim startOffset As Long: startOffset = lastRow + 1 ' 0-based
Do ' Loop invariant: startOffset>=0 and all rows after startOffset are blank (i.e. wholeRng.Rows(i+1) for i>=startOffset)
startOffset = IIf(startOffset - chunkSize >= 0, startOffset - chunkSize, 0)
' Fill `vals(1 To chunkSize, 1 To 1)` with column's rows indexed `[startOffset+1 .. startOffset+chunkSize]` (1-based, inclusive)
Dim chunkRng As Range: Set chunkRng = wholeRng.Resize(chunkSize).Offset(startOffset)
Dim vals() As Variant
If chunkSize > 1 Then
vals = chunkRng.Value2
Else ' reading a 1-cell range requires special handling <http://www.cpearson.com/excel/ArraysAndRanges.aspx>
ReDim vals(1 To 1, 1 To 1)
vals(1, 1) = chunkRng.Value2
End If
Dim i As Long
For i = UBound(vals, 1) To LBound(vals, 1) Step -1
If Not IsEmpty(vals(i, 1)) Then
getLastNonblankRowInColumn = startOffset + i
Exit Function
End If
Next i
If chunkSize < MAX_CHUNK_SIZE Then chunkSize = chunkSize * 2
Loop While startOffset > 0
getLastNonblankRowInColumn = 0
End Function
1
Public Function GetLastRow(ByVal SheetName As String) As Integer
Dim sht As Worksheet
Dim FirstUsedRow As Integer 'the first row of UsedRange
Dim UsedRows As Integer ' number of rows used
Set sht = Sheets(SheetName)
''UsedRange.Rows.Count for the empty sheet is 1
UsedRows = sht.UsedRange.Rows.Count
FirstUsedRow = sht.UsedRange.Row
GetLastRow = FirstUsedRow + UsedRows - 1
Set sht = Nothing
End Function
Sub GetLastRow(strSheet, strColumn)
Dim MyRange As Range
Dim lngLastRow As Long
Set MyRange = Worksheets(strSheet).Range(strColumn & "1")
lngLastRow = Cells(Rows.Count, MyRange.Column).End(xlUp).Row
End Sub
Function LastRow(rng As Range) As Long
Dim iRowN As Long
Dim iRowI As Long
Dim iColN As Integer
Dim iColI As Integer
iRowN = 0
iColN = rng.Columns.count
For iColI = 1 To iColN
iRowI = rng.Columns(iColI).Offset(65536 - rng.Row, 0).End(xlUp).Row
If iRowI > iRowN Then iRowN = iRowI
Next
LastRow = iRowN
End Function
Sub Macro1
Sheets("Sheet1").Select
MsgBox "The last row found is: " & Last(1, ActiveSheet.Cells)
MsgBox "The last column (R1C1) found is: " & Last(2, ActiveSheet.Cells)
MsgBox "The last cell found is: " & Last(3, ActiveSheet.Cells)
MsgBox "The last column (A1) found is: " & Last(4, ActiveSheet.Cells)
End Sub
Function Last(choice As Integer, rng As Range)
' 1 = last row
' 2 = last column (R1C1)
' 3 = last cell
' 4 = last column (A1)
Dim lrw As Long
Dim lcol As Integer
Select Case choice
Case 1:
On Error Resume Next
Last = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByRows, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Row
On Error GoTo 0
Case 2:
On Error Resume Next
Last = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByColumns, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Column
On Error GoTo 0
Case 3:
On Error Resume Next
lrw = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByRows, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Row
lcol = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByColumns, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Column
Last = Cells(lrw, lcol).Address(False, False)
If Err.Number > 0 Then
Last = rng.Cells(1).Address(False, False)
Err.Clear
End If
On Error GoTo 0
Case 4:
On Error Resume Next
Last = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByColumns, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Column
On Error GoTo 0
Last = R1C1converter("R1C" & Last, 1)
For i = 1 To Len(Last)
s = Mid(Last, i, 1)
If Not s Like "#" Then s1 = s1 & s
Next i
Last = s1
End Select
End Function
Function R1C1converter(Address As String, Optional R1C1_output As Integer, Optional RefCell As Range) As String
'Converts input address to either A1 or R1C1 style reference relative to RefCell
'If R1C1_output is xlR1C1, then result is R1C1 style reference.
'If R1C1_output is xlA1 (or missing), then return A1 style reference.
'If RefCell is missing, then the address is relative to the active cell
'If there is an error in conversion, the function returns the input Address string
Dim x As Variant
If RefCell Is Nothing Then Set RefCell = ActiveCell
If R1C1_output = xlR1C1 Then
x = Application.ConvertFormula(Address, xlA1, xlR1C1, , RefCell) 'Convert A1 to R1C1
Else
x = Application.ConvertFormula(Address, xlR1C1, xlA1, , RefCell) 'Convert R1C1 to A1
End If
If IsError(x) Then
R1C1converter = Address
Else
'If input address is A1 reference and A1 is requested output, then Application.ConvertFormula
'surrounds the address in single quotes.
If Right(x, 1) = "'" Then
R1C1converter = Mid(x, 2, Len(x) - 2)
Else
x = Application.Substitute(x, "$", "")
R1C1converter = x
End If
End If
End Function
3
sub test()
msgbox Worksheets("sheet_name").Range("A65536").End(xlUp).Row
end sub
12 回答
简单快捷：
使用示例：
用法：
用法：
?lastdata(activecell.EntireColumn).Address所有依赖于内置行为的解决方案（如
.Find和.End）都有一些没有详细记录的限制（有关详细信息，请参阅my other answer） .我需要一些东西：
在 specific column 中查找最后一个 non-empty 单元格（即具有任何公式或值，即使它是空字符串）
依赖具有明确定义行为的基元
可靠地使用自动过滤器和用户修改
在10,000行上尽可能快地运行（在
Worksheet_Change处理程序中运行而不会感觉迟钝）......性能没有从悬崖上掉下来，意外的数据或格式放在工作表的最后（约1M行）
解决方案如下：
使用
UsedRange查找行号的上限（以便在接近使用范围结束的常见情况下快速搜索真"last row"）;向后返回以查找给定列中包含数据的行;
...使用VBA数组来避免单独访问每一行（如果_549809中有很多行我们需要跳过）
（没有测试，对不起）
sheet.UsedRange.Rows.Count：重新使用的行数，不包括使用的第一行上方的空行
如果第1行为空，并且最后使用的行为10，则UsedRange.Rows.Count将返回9，而不是10 .
此函数计算UsedRange的第一行数加上UsedRange行的数量 .
怎么样：
评论
这个
即使最后一行中只有一个单元格有数据，也会返回最后一个单元格的行号 .
我想使用
UsedRange添加一个更可靠的方法来查找最后使用的行：与查找上次使用的列类似，您可以see this
立即窗口中的结果：
这是查找最后一行，最后一列或最后一个单元格的解决方案 . 它解决了它找到的列的A1 R1C1参考样式困境 . 希望我能给予信任，但无法找到/记住我从哪里得到它，所以“谢谢！”无论是谁在那里发布了原始代码 .
由于“A65536”，这是在A列中寻找值
第一个函数将光标移动到列中的最后一个非空行 . 第二个函数打印列的行 .
你应该使用
.End(xlup)但不是使用65536你可能想要使用：这样它适用于Excel 2007，我认为它有超过65536行