当用户选择'0'时,我需要从 case 4
中的无限循环返回到我之前的开关案例 . 我怎样才能做到这一点?
#include <iostream>
using namespace std;
struct Node {
int data;
Node* next;
}* head = NULL;
int main()
{
Node *temp, *x;
int flag;
while (1) {
cout << "Main Menu\n1. Insert Node\n2. Show the list\n3. Search Node\n4. Update\n5. Delete Node \n6. Exit\n";
int option;
cout << "Choice your option" << endl;
cin >> option;
switch (option) {
case 1:
if (head == NULL) {
temp = new Node;
cin >> temp->data;
temp->next = NULL;
head = temp;
x = head;
}
else {
temp = new Node;
cin >> temp->data;
temp->next = NULL;
x->next = temp;
x = x->next;
}
break;
case 2:
cout << "List Showing Blew:" << endl;
x = head;
while (x != NULL) {
cout << x->data << " ";
x = x->next;
}
cout << endl;
break;
case 3:
cout << "Which value do you want to search:" << endl;
int find;
cin >> find;
x = head;
flag = 0;
while (x != NULL) {
if (x->data == find) {
flag = 1;
}
x = x->next;
}
if (flag == 1) {
cout << "Value Found" << endl;
}
else {
cout << "Value Not Found" << endl;
}
break;
case 4:
cout << "Update Node" << endl;
while (1) {
cout << "Update Menu\n1. Sort Node As Ascending Order\n2. Sort Node As Descending Order\n0. Exit\nChoice your option:";
int updateOption;
cin >> updateOption;
switch (updateOption) {
case 1:
cout << "Ascending Order" << endl;
break;
case 2:
cout << "Descending Order" << endl;
break;
case 0:
switch (option = 1)
;
break;
default:
cout << "Invalid Input!!!" << endl;
break;
}
}
break;
case 5:
cout << "Case 4" << endl;
break;
case 6:
cout << "Case 5" << endl;
break;
case 7:
cout << "Case 6" << endl;
break;
default:
cout << "Invalid grade" << endl;
break;
}
}
return 0;
}