There is a small error in Tri Q's Algorithm. 找到孩子后,如果childrenCount> 1并且我们再次迭代,我们可以覆盖正确找到的孩子 . 因此我在我的代码中添加了 if (foundChild != null) break; 来处理这种情况 .
/// <summary>
/// Finds a Child of a given item in the visual tree.
/// </summary>
/// <param name="parent">A direct parent of the queried item.</param>
/// <typeparam name="T">The type of the queried item.</typeparam>
/// <param name="childName">x:Name or Name of child. </param>
/// <returns>The first parent item that matches the submitted type parameter.
/// If not matching item can be found,
/// a null parent is being returned.</returns>
public static T FindChild<T>(DependencyObject parent, string childName)
where T : DependencyObject
{
// Confirm parent and childName are valid.
if (parent == null) return null;
T foundChild = null;
int childrenCount = VisualTreeHelper.GetChildrenCount(parent);
for (int i = 0; i < childrenCount; i++)
{
var child = VisualTreeHelper.GetChild(parent, i);
// If the child is not of the request child type child
T childType = child as T;
if (childType == null)
{
// recursively drill down the tree
foundChild = FindChild<T>(child, childName);
// If the child is found, break so we do not overwrite the found child.
if (foundChild != null) break;
}
else if (!string.IsNullOrEmpty(childName))
{
var frameworkElement = child as FrameworkElement;
// If the child's name is set for search
if (frameworkElement != null && frameworkElement.Name == childName)
{
// if the child's name is of the request name
foundChild = (T)child;
break;
}
}
else
{
// child element found.
foundChild = (T)child;
break;
}
}
return foundChild;
}
public static class UIHelper
{
/// <summary>
/// Finds a parent of a given item on the visual tree.
/// </summary>
/// <typeparam name="T">The type of the queried item.</typeparam>
/// <param name="child">A direct or indirect child of the queried item.</param>
/// <returns>The first parent item that matches the submitted type parameter.
/// If not matching item can be found, a null reference is being returned.</returns>
public static T FindVisualParent<T>(DependencyObject child)
where T : DependencyObject
{
// get parent item
DependencyObject parentObject = VisualTreeHelper.GetParent(child);
// we’ve reached the end of the tree
if (parentObject == null) return null;
// check if the parent matches the type we’re looking for
T parent = parentObject as T;
if (parent != null)
{
return parent;
}
else
{
// use recursion to proceed with next level
return FindVisualParent<T>(parentObject);
}
}
}
public static class UIChildFinder
{
public static DependencyObject FindChild(this DependencyObject reference, string childName, Type childType)
{
DependencyObject foundChild = null;
if (reference != null)
{
int childrenCount = VisualTreeHelper.GetChildrenCount(reference);
for (int i = 0; i < childrenCount; i++)
{
var child = VisualTreeHelper.GetChild(reference, i);
// If the child is not of the request child type child
if (child.GetType() != childType)
{
// recursively drill down the tree
foundChild = FindChild(child, childName, childType);
}
else if (!string.IsNullOrEmpty(childName))
{
var frameworkElement = child as FrameworkElement;
// If the child's name is set for search
if (frameworkElement != null && frameworkElement.Name == childName)
{
// if the child's name is of the request name
foundChild = child;
break;
}
}
else
{
// child element found.
foundChild = child;
break;
}
}
}
return foundChild;
}
}
public static IEnumerable<T> FindVisualChildren<T>(DependencyObject parent)
where T : DependencyObject
{
int childrenCount = VisualTreeHelper.GetChildrenCount(parent);
for (int i = 0; i < childrenCount; i++)
{
var child = VisualTreeHelper.GetChild(parent, i);
var childType = child as T;
if (childType != null)
{
yield return (T)child;
}
foreach (var other in FindVisualChildren<T>(child))
{
yield return other;
}
}
}
-4
我编辑了CrimsonX的代码,因为它不适用于超类类型:
public static T FindChild<T>(DependencyObject depObj, string childName)
where T : DependencyObject
{
// Confirm obj is valid.
if (depObj == null) return null;
// success case
if (depObj is T && ((FrameworkElement)depObj).Name == childName)
return depObj as T;
for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
{
DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
//DFS
T obj = FindChild<T>(child, childName);
if (obj != null)
return obj;
}
return null;
}
/// <summary>
/// Helper methods for UI-related tasks.
/// </summary>
public static class UIHelper
{
/// <summary>
/// Finds a parent of a given item on the visual tree.
/// </summary>
/// <typeparam name="T">The type of the queried item.</typeparam>
/// <param name="child">A direct or indirect child of the
/// queried item.</param>
/// <returns>The first parent item that matches the submitted
/// type parameter. If not matching item can be found, a null
/// reference is being returned.</returns>
public static T TryFindParent<T>(DependencyObject child)
where T : DependencyObject
{
//get parent item
DependencyObject parentObject = GetParentObject(child);
//we've reached the end of the tree
if (parentObject == null) return null;
//check if the parent matches the type we're looking for
T parent = parentObject as T;
if (parent != null)
{
return parent;
}
else
{
//use recursion to proceed with next level
return TryFindParent<T>(parentObject);
}
}
/// <summary>
/// This method is an alternative to WPF's
/// <see cref="VisualTreeHelper.GetParent"/> method, which also
/// supports content elements. Do note, that for content element,
/// this method falls back to the logical tree of the element!
/// </summary>
/// <param name="child">The item to be processed.</param>
/// <returns>The submitted item's parent, if available. Otherwise
/// null.</returns>
public static DependencyObject GetParentObject(DependencyObject child)
{
if (child == null) return null;
ContentElement contentElement = child as ContentElement;
if (contentElement != null)
{
DependencyObject parent = ContentOperations.GetParent(contentElement);
if (parent != null) return parent;
FrameworkContentElement fce = contentElement as FrameworkContentElement;
return fce != null ? fce.Parent : null;
}
//if it's not a ContentElement, rely on VisualTreeHelper
return VisualTreeHelper.GetParent(child);
}
}
public static T FindVisualAncestorOfType<T>(this DependencyObject Elt)
where T : DependencyObject
{
for (DependencyObject parent = VisualTreeHelper.GetParent(Elt);
parent != null; parent = VisualTreeHelper.GetParent(parent))
{
T result = parent as T;
if (result != null)
return result;
}
return null;
}
private void ItemsControlItem_Loaded(object sender, RoutedEventArgs e)
{
if (SomeCondition())
{
var children = (sender as Panel).Children;
var child = (from Control child in children
where child.Name == "NameTextBox"
select child).First();
child.Focus();
}
}
或者当然是明显的循环迭代儿童 .
17
这是一个使用灵活谓词的解决方案:
public static DependencyObject FindChild(DependencyObject parent, Func<DependencyObject, bool> predicate)
{
if (parent == null) return null;
int childrenCount = VisualTreeHelper.GetChildrenCount(parent);
for (int i = 0; i < childrenCount; i++)
{
var child = VisualTreeHelper.GetChild(parent, i);
if (predicate(child))
{
return child;
}
else
{
var foundChild = FindChild(child, predicate);
if (foundChild != null)
return foundChild;
}
}
return null;
}
你可以这样称呼它:
var child = FindChild(parent, child =>
{
var textBlock = child as TextBlock;
if (textBlock != null && textBlock.Name == "MyTextBlock")
return true;
else
return false;
}) as TextBlock;
2
这些选项已经讨论过在C#中遍历Visual Tree . 它也可以使用RelativeSource标记扩展来遍历xaml中的可视化树 . msdn
public static T FindChild<T>(DependencyObject parent, string childName)
where T : DependencyObject
{
// Confirm parent and childName are valid.
if (parent == null) return null;
T foundChild = null;
int childrenCount = VisualTreeHelper.GetChildrenCount(parent);
for (int i = 0; i < childrenCount; i++)
{
var child = VisualTreeHelper.GetChild(parent, i);
// If the child is not of the request child type child
T childType = child as T;
if (childType == null)
{
// recursively drill down the tree
foundChild = FindChild<T>(child, childName);
// If the child is found, break so we do not overwrite the found child.
if (foundChild != null) break;
}
else if (!string.IsNullOrEmpty(childName))
{
var frameworkElement = child as FrameworkElement;
// If the child's name is set for search
if (frameworkElement != null && frameworkElement.Name == childName)
{
// if the child's name is of the request name
foundChild = (T)child;
break;
}
// recursively drill down the tree
foundChild = FindChild<T>(child, childName);
// If the child is found, break so we do not overwrite the found child.
if (foundChild != null) break;
else
{
// child element found.
foundChild = (T)child;
break;
}
}
return foundChild;
}
如果类型匹配但名称不匹配,则需要继续以递归方式调用该方法(当您将 FrameworkElement 作为 T 传递时会发生这种情况) . 否则它会返回 null 而这是错误的 .
16
要从代码中查找给定类型的祖先,您可以使用:
[CanBeNull]
public static T FindAncestor<T>(DependencyObject d) where T : DependencyObject
{
while (true)
{
d = VisualTreeHelper.GetParent(d);
if (d == null)
return null;
var t = d as T;
if (t != null)
return t;
}
}
此实现使用迭代而不是递归,这可能稍微快一些 .
如果您使用的是C#7,可以稍微缩短一下:
[CanBeNull]
public static T FindAncestor<T>(DependencyObject d) where T : DependencyObject
{
while (true)
{
d = VisualTreeHelper.GetParent(d);
if (d == null)
return null;
if (d is T t)
return t;
}
}
11
试试这个
<TextBlock x:Name="txtblock" FontSize="24" >Hai Welcom to this page
</TextBlock>
代码背后
var txtblock = sender as Textblock;
txtblock.Foreground = "Red"
18 回答
我结合了John Myczek使用的模板格式和上面的Tri Q算法来创建一个可以在任何父级上使用的findChild算法 . 请记住,向下递归搜索树可能是一个漫长的过程 . 我只是在WPF应用程序上对此进行了检查,请对您可能发现的任何错误发表评论,我将更正我的代码 .
WPF Snoop是查看可视化树的有用工具 - 我强烈建议在测试或使用此算法检查您的工作时使用它 .
There is a small error in Tri Q's Algorithm. 找到孩子后,如果childrenCount> 1并且我们再次迭代,我们可以覆盖正确找到的孩子 . 因此我在我的代码中添加了
if (foundChild != null) break;
来处理这种情况 .这样叫:
注意
Application.Current.MainWindow
可以是任何父窗口 .您还可以使用FrameworkElement.FindName(string)按名称查找元素 .
鉴于:
在代码隐藏文件中,您可以编写:
当然,因为它是使用x:Name定义的,所以你可以只引用生成的字段,但也许你想要动态地而不是静态地查找它 .
此方法也适用于模板,其中命名项目多次出现(每次使用模板一次) .
您可以使用VisualTreeHelper查找控件 . 下面是一个使用VisualTreeHelper查找指定类型的父控件的方法 . 您也可以使用VisualTreeHelper以其他方式查找控件 .
这样叫:
我可能只是重复其他所有人,但我确实有一段很好的代码,它使用FindChild()方法扩展DependencyObject类,它将按类型和名称为您提供子类 . 只是包括和使用 .
希望你觉得它有用 .
我对代码的扩展 .
添加重载以按类型,按类型和条件(谓词)查找一个子项,查找符合条件的所有类型的子项
FindChildren方法除了是DependencyObject的扩展方法外,还是一个迭代器
FindChildren也走逻辑子树 . 请参阅博客文章中链接的Josh Smith的帖子 .
资料来源:https://code.google.com/p/gishu-util/source/browse/#git%2FWPF%2FUtilities
解释性博文:http://madcoderspeak.blogspot.com/2010/04/wpf-find-child-control-of-specific-type.html
如果要查找特定类型的所有控件,您可能也对此代码段感兴趣
我编辑了CrimsonX的代码,因为它不适用于超类类型:
这将忽略一些元素 - 您应该像这样扩展它以支持更广泛的控件 . 如需简短的讨论,请看看here
虽然我喜欢一般的递归,但它在用C#编程时不如迭代效率高,所以下面的解决方案可能比John Myczek建议的更简洁?这将从给定控件中搜索层次结构以查找特定类型的祖先控件 .
像这样调用它来查找包含名为
ExampleTextBox
的控件的Window
:这是我的代码,通过类型查找控件,同时控制我们进入层次结构的深度(maxDepth == 0表示无限深) .
exciton80 ...我的代码没有通过usercontrols递归出现问题 . 它击中了Grid根并抛出错误 . 我相信这可以解决它:
我有这样的序列函数(这是完全一般的):
立即生孩子:
在分层树上寻找所有孩子:
您可以在Window上调用它来获取所有控件 .
收集完成后,可以使用LINQ(即OfType,Where) .
由于问题足够普遍,它可能会吸引人们寻找非常微不足道的案例的答案:如果你只想要一个孩子而不是一个后代,你可以使用Linq:
或者当然是明显的循环迭代儿童 .
这是一个使用灵活谓词的解决方案:
你可以这样称呼它:
这些选项已经讨论过在C#中遍历Visual Tree . 它也可以使用RelativeSource标记扩展来遍历xaml中的可视化树 . msdn
按类型查找
这段代码只修复了@CrimsonX回答的错误:
如果类型匹配但名称不匹配,则需要继续以递归方式调用该方法(当您将
FrameworkElement
作为T
传递时会发生这种情况) . 否则它会返回null
而这是错误的 .要从代码中查找给定类型的祖先,您可以使用:
此实现使用迭代而不是递归,这可能稍微快一些 .
如果您使用的是C#7,可以稍微缩短一下:
试试这个
代码背后