SDL2不会正确绘制矩形-Java 学习之路

我正在创建一个窗口并绘制一个框但是由于某种原因而不是绘制一个框，屏幕只是改为那种颜色 . 我附上了一张窗口外观的照片，我将附上源代码 .

#include <iostream>
#include <SDL.h>
#undef main

using namespace std;
int SCREEN_WIDTH = 650;
int SCREEN_HEIGHT = 650;

int main() {
    if (SDL_Init(SDL_INIT_VIDEO) != 0) {
        std::cout << "SDL_Init Error: " << SDL_GetError() << std::endl;

        return 1;
    }

    SDL_Window *window = SDL_CreateWindow("Cells", 100, 100, SCREEN_WIDTH, SCREEN_HEIGHT, SDL_WINDOW_SHOWN);
    if (window == nullptr) {
        std::cout << "SDL_CreateWindow Error: " << SDL_GetError() << std::endl;

        SDL_Quit();

        return 1;
    }

    SDL_Renderer *renderer = SDL_CreateRenderer(window, -1, SDL_RENDERER_ACCELERATED | SDL_RENDERER_PRESENTVSYNC);
    if (renderer == nullptr) {
        std::cout << "SDL_CreateRenderer Error: " << SDL_GetError() << std::endl;

        SDL_DestroyWindow(window);
        SDL_Quit();

        return 1;
    }

    SDL_Event event;
    bool quit = false;

    while (!quit) {
        while (SDL_PollEvent(&event)) {
            if (event.type == SDL_QUIT) {
                quit = true;
            }
        }

        SDL_RenderClear(renderer);
        // renderTextures
        SDL_Rect fillRect = { 122, 122, 122, 122};
        SDL_SetRenderDrawColor(renderer, 255, 255, 255, 255);
        SDL_RenderFillRect(renderer, &fillRect);
        SDL_RenderPresent(renderer);
    }

    return 0;
}

Doesn't Draw Correctly

1 回答

3
SDL_RenderClear使用您修改过的当前绘制颜色，因此您的透明和矩形颜色是相同的 . 设置不同的清晰颜色（您想要在背景中没有其他任何东西绘制的颜色），例如
```
SDL_SetRenderDrawColor(renderer, 0, 0, 0, 255);
    SDL_RenderClear(renderer);
    // now draw your rectangles with different col
```
回复于 2024-05-13T16:44:39+08:00

SDL2不会正确绘制矩形

1 回答

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