我想做的就是能够计算每个点之间的距离,这样如果用户愿意,可以显示总距离 . 为了澄清,距离将是(Point1-> Point2)(Point2-> Point3)(Point3-> Point4),而不是Point1-> Point4 . 我相信我必须使用这样的等式:
distance = sqrt((int)(...计算一些短值...)
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
typedef struct point
{
short int x;
short int y;
}point;
int main(char ** args, int argc)
{
point append;
char choice;
int i = 1;
int c;
char dump;
while(i != 0)
{
printf("Enter a to append and c to calculate p to print\n:");
scanf("%c%c", &choice, &dump);
switch(choice)
{
case 'a':
{
FILE * output;
output = fopen("test.bin", "ab+");
printf("Enter the x:\n");
scanf("%hu", &append.x);
printf("Enter the y:\n");
scanf("%hu%c", &append.y, &dump);
fprintf(output, "Point (%hu,%hu)\n", append.x, append.y);
fclose(output);
break;
}
case 'p':
{
FILE * print;
print = fopen("test.bin", "rb");
if(print)
{
while((c = getc(print)) != EOF)
{
putchar(c);
}
}
fclose(print);
break;
}
case 'q':
{
i = 0;
break;
}
}
}
}
1 回答
使用distance formula查找每个段的长度 . 添加这些段长度以查找总距离 .
距离公式取x和y中变化的平方和的平方根:
dx
是x2-x1
而dy
是y2-y1
.