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与firestore本地反应得到在线用户数

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我用firebase / firestore构建了本地应用程序 . 我正在寻找一种方法来检查应用程序中的在线用户数,所以我找到了一种方法来处理this tutorial

var userRef = new Firebase('https://<demo>.firebaseio.com/presence/' + userid);
userRef.on('value', function(snapshot) {
  if (snapshot.val() === true) {
    // User is online, update UI.
  } else {
    // User logged off at snapshot.val() - seconds since epoch.
  }
});

我正在寻找与firestore相关的方法并做出反应 . 有什么实现我可以看到怎么做?

我发现这种方式与firestore有关

import { Platform } from 'react-native';
import firebase from 'react-native-firebase';


function rtdb_and_local_fs_presence() {
    // [START rtdb_and_local_fs_presence]
    // [START_EXCLUDE]
    var uid = firebase.auth().currentUser.uid;
    console.log('uid',uid)
    var userStatusDatabaseRef = firebase.database().ref('status/' + uid);

    var isOfflineForDatabase = {
        state: 'offline',
        last_changed: firebase.database.ServerValue.TIMESTAMP,
    };

    var isOnlineForDatabase = {
        state: 'online',
        last_changed: firebase.database.ServerValue.TIMESTAMP,
    };

    // [END_EXCLUDE]
    var userStatusFirestoreRef = firebase.firestore().doc('status/' + uid);

    // Firestore uses a different server timestamp value, so we'll 
    // create two more constants for Firestore state.
    var isOfflineForFirestore = {
        state: 'offline',
        last_changed: firebase.firestore.FieldValue.serverTimestamp(),
    };

    var isOnlineForFirestore = {
        state: 'online',
        last_changed: firebase.firestore.FieldValue.serverTimestamp(),
    };

    firebase.database().ref('.info/connected').on('value', function(snapshot) {
        if (snapshot.val() == false) {
            // Instead of simply returning, we'll also set Firestore's state
            // to 'offline'. This ensures that our Firestore cache is aware
            // of the switch to 'offline.'
            userStatusFirestoreRef.set(isOfflineForFirestore);
            return;
        };

        userStatusDatabaseRef.onDisconnect().set(isOfflineForDatabase).then(function() {
            userStatusDatabaseRef.set(isOnlineForDatabase);

            // We'll also add Firestore set here for when we come online.
            userStatusFirestoreRef.set(isOnlineForFirestore);
        });
    });
    // [END rtdb_and_local_fs_presence]
}

function fs_listen() {
    var uid = firebase.auth().currentUser.uid;
    var userStatusFirestoreRef = firebase.firestore().doc('status/' + uid);

    // [START fs_onsnapshot]
    userStatusFirestoreRef.onSnapshot(function(doc) {
        var isOnline = doc.data().state == 'online';
        // ... use isOnline
    });
}


firebase.auth().signInAnonymouslyAndRetrieveData().then((user) => {
    rtdb_and_local_fs_presence();
    fs_listen();
});

当我在线时,它确实使用正确的uid更新状态集合,但是当我从应用程序断开连接时,它不会更新为脱机状态 . 我怎样才能做到这一点?

1 回答

  • 0

    当用户完全关闭应用程序时它将起作用 .

    onStatusOffline(user){
         firebase.database().ref(`users/${user.uid}`) 
         .onDisconnect()
         .update({
             online: false,
         });
    }
    

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