我的照片尺寸各不相同,它们可以是横向,纵向或正方形,我需要为每张照片制作最适合的水印 - 所以我需要调整水印的宽度(没有Imagick),因为它是一个长矩形,所以身高无关紧要 .
我找到了PHP函数 imagecopyresized
,但是我'll be honest, I can'找出了我的情况所需的参数,即使在查看PHP文档之后!我也不确定在使用imagecopyresized后,我的其余功能将在获得水印宽度和高度的地方工作 .
有人可以帮助我超越终点线 . 这是我得到了多远,它需要的是添加到 imagecopyresized
部分的正确参数:
<?php
header('content-type: image/jpeg');
$image = imagecreatefromjpeg('https://.....jpg');
$imageSize = getimagesize('https://.....jpg');
$newWatermarkWidth = $imageSize[0]-50; // width of image minus 50px
$watermark = imagecreatefrompng('watermark.png');
// resize watermark to newWatermarkWidth here with imagecopyresize
$watermark = imagecopyresized(?,?,?,?);
$watermark_width = imagesx($watermark);
$watermark_height = imagesy($watermark);
$dest_x = ($imageSize[0]/2) - ($watermark_width/2) ;
$dest_y = ($imageSize[1]/2) - ($watermark_height/2);
imagecopy($image, $watermark, round($dest_x,0), round($dest_y,0), 0, 0, $watermark_width, $watermark_height);
imagejpeg($image);
imagedestroy($image);
imagedestroy($watermark);
?>
THIS IS WHAT I ENDED WITH & WORKS PERFECTLY
一个脚本,用于调整水印宽度以适应整个父图像,居中且成比例 .
<?php
header('content-type: image/jpeg');
$image = imagecreatefromjpeg('http://mydomain.com/myPhoto.jpg');
$imageSize = getimagesize('http://mydomain.com/myPhoto.jpg');
$watermark = imagecreatefrompng('http://mydomain.com/myWatermark.png');
$watermark_o_width = imagesx($watermark);
$watermark_o_height = imagesy($watermark);
$newWatermarkWidth = $imageSize[0]-20;
$newWatermarkHeight = $watermark_o_height * $newWatermarkWidth / $watermark_o_width;
imagecopyresized($image, $watermark, $imageSize[0]/2 - $newWatermarkWidth/2, $imageSize[1]/2 - $newWatermarkHeight/2, 0, 0, $newWatermarkWidth, $newWatermarkHeight, imagesx($watermark), imagesy($watermark));
imagejpeg($image);
imagedestroy($image);
imagedestroy($watermark);
1 回答
这会调整水印的大小并直接复制到图像 .
您不再需要现有的imagecopy线 .