正则表达式找到所有匹配
我需要一个正则表达式来查找我的模式的所有匹配项 .
文字是这样的:
"someother text !style_delete [company code : 43ev4] between text !style_delete [organiztion : 0asj9] end of line text"
我想找到该模式的所有匹配项:
!style_delete [.*]
我试过这样的:
Pattern pattern = Pattern.compile("!style_delete\\s*\\[.*\\]");
有了这个匹配文本就像这样:
!style_delete [company code : 43ev4] between text !style_delete [organiztion : 0asj9]
但我预计如下:
match 1 : !style_delete [company code : 43ev4]
match 2 : !style_delete [organiztion : 0asj9]
请帮助我,java中的正则表达式将获得以上输出 .
回答(3)
@Test
public void test() {
final String input = "someother text !style_delete [company code : 43ev4] between text !style_delete [organiztion : 0asj9] end of line text";
// my regexp:strong text
// final String regex = "(!style_delete\\s\\[[a-zA-Z0-9\\s:]*\\])";
// regexp from Trinmon:
final String regex = "(!style_delete\\s*\\[[^\\]]*\\])";
final Matcher m = Pattern.compile(regex).matcher(input);
final List<String> matches = new ArrayList<>();
while (m.find()) {
matches.add(m.group(0));
}
assertEquals(2, matches.size());
assertEquals("match 1: ", matches.get(0), "!style_delete [company code : 43ev4]");
assertEquals("match 2: ", matches.get(1), "!style_delete [organiztion : 0asj9]");
}
edit
也许Trinimon的答案模式更优雅一点 . 我用正则表达式更新了正则表达式 .
2 years ago
您需要使用non-greedy匹配:
在您的情况下,模式是:
证明(Java 7):
链接到证据:http://ideone.com/Qtymb3