php curl issue curl_init上的资源ID＃2

3 回答

• 1

  尝试使用curl_error（$ ch）和echo来诊断错误

  $ch= curl_init();
  curl_setopt($ch, CURLOPT_URL, $url);
  curl_setopt($ch, CURLOPT_TIMEOUT, 30);
  curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 30);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
  curl_setopt($ch, CURLOPT_HEADER, 0);
  )                                                                       
  );     
  
  $response = curl_exec($ch);
  $err_status = curl_error($ch);
  echo $err_status;
  curl_close($ch);
  

  回复于 2024-05-06T09:03:16+08:00
• 2

  curl_init 成功时返回 cURL 句柄，错误时返回FALSE . 因此 echo $ch; 将返回类似资源ID＃2的内容 .

  见http://php.net/manual/en/function.curl-init.php

  你必须尝试这样的事情

  $url = "https://example.com:4433/deviceservice/authorize?login=query"; // URL JSON
  
  $ch = curl_init();
  
  curl_setopt($ch, CURLOPT_URL, $url);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
  curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, TRUE);
  curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, TRUE);
  $json = curl_exec( $ch );
  $json = json_decode($json);
  curl_close($ch);   
  
  if(empty($json)){
     echo 'nothing';
  }
  

  回复于 2024-05-06T09:03:16+08:00
• 1

  如果您不在使用SSL的主机上，则应绕过SSL验证

  <?php
      $url = "https://example.com:4433/deviceservice/authorize?login=query"; 
      $ch = curl_init($url);
      echo $ch; //write Resource id # 2
      if( $ch )
      {
          curl_setopt( $ch, CURLOPT_RETURNTRANSFER, 1 );
          curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
          curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE);
          $json = curl_exec( $ch );
          $json = json_decode($json);
      } else {
          echo 'nothing';
      }
  

  回复于 2024-05-06T09:03:16+08:00