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有没有办法在javascript中清理子类参数？

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我正在努力在JavaScript中使用子类，我正在使用漫威电影来完成它 . 这是我的超类：

class Episode {
  constructor(title, releaseDate, storyYear, phase, order, runtime, hero){
    this.title = title;
    this.releaseDate = releaseDate;
    this.releaseMonth = parseInt(releaseDate.split('/')[0]);
    this.releaseYear = parseInt(releaseDate.split('/')[1]);
    this.episodeType = "";
    this.storyYear = storyYear;
    this.phase = phase;
    this.order = order;
    this.runtime = runtime;
    this.hours = parseInt(runtime.split(':')[0]);
    this.minutes = parseInt(runtime.split(':')[1]);
    this.hero = hero;
  }
}

现在我创建了3个子类 . 一部用于电影，一部用于电视节目，一部用于“一次拍摄” . 通过这种方式，我可以添加额外的信息，例如电视季节，剧集以及单拍的DVD .

class Movie extends Episode {
    constructor(title, releaseYear, storyYear, phase, order, runtime, hero){
      super(title, releaseYear, storyYear, phase, order, runtime, hero);
      this.episodeType = "Movie";
    }
  }
  class TVShow extends Episode {
    constructor(title, releaseYear, storyYear, phase, order, runtime, hero, episode){
      super(title, releaseYear, storyYear, phase, order, runtime, hero);
      this.episodeType = "TV Show";
      this.episode = episode;
    }
  }
  class OneShot extends Episode {
    constructor(title, releaseYear, storyYear, phase, order, runtime, hero){
      super(title, releaseYear, storyYear, phase, order, runtime, hero);
      this.episodeType = "One Shot";
    }
  }

我看到的问题是，如果我在原始剧集中添加构造函数，我必须将其添加到每个子类中 . 这是最有效的方法吗？

javascript class parameters subclass superclass

1 回答

  • 0

    正如@Bergi建议您可以使用参数列表而不是显式定义每个参数，例如

    class Episode{
   constructor(args)
   {
      this.args = args;
   }
}


class Movie extends Episode{
   constructor(args){
     args.episodeType = 'Movie';
     super(args);
   }
}

// The same for all subclasses

    通过这种方式，您可以获得更清晰的代码并避免将所有参数列出到处 . 但是，您将丢失所有参数的隐式定义，并且可能希望手动实现某些约束 . 例如如果 args.title 未定义或为空，则抛出错误 .

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