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在Swift中实例化和呈现viewController

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问题

我开始在 Xcode 6 上看一下新的 Swift ，我尝试了一些演示项目和教程 . 现在我被困在：

Instantiating and then presenting a viewController from a specific storyboard

Objective-C解决方案

UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"myStoryboardName" bundle:nil];
UIViewController *vc = [storyboard instantiateViewControllerWithIdentifier:@"myVCID"];
[self presentViewController:vc animated:YES completion:nil];

如何在Swift上实现这一目标？

ios objective-c swift uiviewcontroller

14 回答

  • 2

    斯威夫特4：

    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    let yourVC: YourVC = storyboard.instantiateViewController(withIdentifier: "YourVC") as! YourVC
    回复于
  • 550

    这一切都是新语法的问题，功能没有改变：

    // Swift 3.0

let storyboard = UIStoryboard(name: "MyStoryboardName", bundle: nil)
let controller = storyboard.instantiateViewController(withIdentifier: "someViewController")
self.present(controller, animated: true, completion: nil)

    如果您遇到 init(coder:) 的问题，请参阅EridB's answer .

    回复于
  • 14

    对于使用@akashivskyy's answer来实例化 UIViewController 并且有异常的人：

    致命错误：在课堂上使用未实现的初始化程序'init（coder :)'

    Quick tip:

    在您尝试实例化的目标 UIViewController 上手动实现 required init?(coder aDecoder: NSCoder)

    required init?(coder aDecoder: NSCoder) {
    super.init(coder: aDecoder)
}

    如果您需要更多描述请参考我的回答here

    回复于
  • 1

    This link has both the implementations:

    迅速：

    let viewController:UIViewController = UIStoryboard(name: "Main", bundle: nil).instantiateViewControllerWithIdentifier("ViewController") as UIViewController
self.presentViewController(viewController, animated: false, completion: nil)

    目标C.

    UIViewController *viewController = [[UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil] instantiateViewControllerWithIdentifier:@"ViewController"];

    This link has code for initiating viewcontroller in the same storyboard

    /*
 Helper to Switch the View based on StoryBoard
 @param StoryBoard ID  as String
*/
func switchToViewController(identifier: String) {
    let viewController = self.storyboard?.instantiateViewControllerWithIdentifier(identifier) as! UIViewController
    self.navigationController?.setViewControllers([viewController], animated: false)

}
    回复于
  • 5

    akashivskyy的答案很好！但是，如果您从显示的视图控制器返回时遇到一些问题，则此替代方法可能会有所帮助 . 它对我有用！

    迅速：

    let storyboard = UIStoryboard(name: "MyStoryboardName", bundle: nil)
let vc = storyboard.instantiateViewControllerWithIdentifier("someViewController") as! UIViewController
// Alternative way to present the new view controller
self.navigationController?.showViewController(vc, sender: nil)

    OBJ-C：

    UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"MyStoryboardName" bundle:nil];
UIViewController *vc = [storyboard instantiateViewControllerWithIdentifier:@"someViewController"];
[self.navigationController showViewController:vc sender:nil];
    回复于
  • 1
    // "Main" is name of .storybord file "
let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
// "MiniGameView" is the ID given to the ViewController in the interfacebuilder
// MiniGameViewController is the CLASS name of the ViewController.swift file acosiated to the ViewController
var setViewController = mainStoryboard.instantiateViewControllerWithIdentifier("MiniGameView") as MiniGameViewController
var rootViewController = self.window!.rootViewController
rootViewController?.presentViewController(setViewController, animated: false, completion: nil)

    当我把它放在AppDelegate中时，这对我来说很好

    回复于
  • 41

    如果你想以模态方式呈现它，你应该有类似下面的东西：

    let vc = self.storyboard!.instantiateViewControllerWithIdentifier("YourViewControllerID")
self.showDetailViewController(vc as! YourViewControllerClassName, sender: self)
    回复于
  • 2

    如果你有一个不使用任何storyboard / Xib的Viewcontroller，你可以像下面这样调用这个特定的VC：

    let vcInstance : UIViewController   = yourViewController()
 self.present(vcInstance, animated: true, completion: nil)
    回复于
  • 1

    我知道这是一个旧线程，但我认为当前的解决方案（使用给定视图控制器的硬编码字符串标识符）非常容易出错 .

    我已经创建了一个构建时脚本（你can access here），它将创建一个编译器安全的方法来访问和实例化给定项目中所有storyboard的视图控制器 .

    例如， Main.storyboard 中名为 vc1 的视图控制器将实例化为：

    let vc: UIViewController = R.storyboard.Main.vc1^  // where the '^' character initialize the controller
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  • 6

    斯威夫特3
    Storyboard

    let settingStoryboard : UIStoryboard = UIStoryboard(name: "SettingViewController", bundle: nil)
let settingVC = settingStoryboard.instantiateViewController(withIdentifier: "SettingViewController") as! SettingViewController
self.present(settingVC, animated: true, completion: {

})
    回复于
  • 10

    无论我尝试什么，它都不适合我 - 没有错误，但我的屏幕上也没有新的视图控制器 . 不知道为什么，但将它包装在超时功能中最终使其工作：

    DispatchQueue.main.asyncAfter(deadline: .now() + 0.0) {
    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    let controller = storyboard.instantiateViewController(withIdentifier: "TabletViewController")
    self.present(controller, animated: true, completion: nil)
}
    回复于
  • 0

    我想建议一个更清洁的方式 . 当我们有多个故事板时，这将非常有用

    1.Create a structure with all your storyboards

    struct Storyboard {
      static let main = "Main"
      static let login = "login"
      static let profile = "profile" 
      static let home = "home"
    }

    2. Create a UIStoryboard extension like this

    extension UIStoryboard {
  @nonobjc class var main: UIStoryboard {
    return UIStoryboard(name: Storyboard.main, bundle: nil)
  }
  @nonobjc class var journey: UIStoryboard {
    return UIStoryboard(name: Storyboard.login, bundle: nil)
  }
  @nonobjc class var quiz: UIStoryboard {
    return UIStoryboard(name: Storyboard.profile, bundle: nil)
  }
  @nonobjc class var home: UIStoryboard {
    return UIStoryboard(name: Storyboard.home, bundle: nil)
  }
}

    将故事板标识符作为类名称，并使用以下代码进行实例化

    let loginVc = UIStoryboard.login.instantiateViewController(withIdentifier: "\(LoginViewController.self)") as! LoginViewController
    回复于
  • 1

    我创建了一个库，可以通过更好的语法更轻松地处理这个问题：

    https://github.com/Jasperav/Storyboardable

    只需更改Storyboard.swift，让 ViewControllers 符合 Storyboardable .

    回复于
  • 0

    Swift 4.2更新了代码

    let storyboard = UIStoryboard(name: "StoryboardNameHere", bundle: nil)
let controller = storyboard.instantiateViewController(withIdentifier: "ViewControllerNameHere")
self.present(controller, animated: true, completion: nil)
    回复于

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