我希望能够将我的表列的名称与我的查询结果一起导出到.csv文件中 . 我找到了一些使用mysql_的例子,但我希望有人可以帮助我,因为我正在尝试使用PDO . 来自$ sql导出的数据就好了,但是我无法将列名作为第一行导出 .
<?php
header("Content-type: text/csv");
header("Content-Disposition: attachment; filename=brewlog.csv");
header("Pragma: no-cache");
header("Expires: 0");
//Database Connection
include"connect.php";
//Assign variables from POST
$beer = $_POST['beer'];
//SQL Query for Data
$sql = "SELECT * FROM brewlog WHERE Beer = :beer ORDER BY BrewDate DESC";
//Prepare Query, Bind Parameters, Excute Query
$STH = $DBH->prepare($sql);
$STH->bindParam(':beer', $beer);
$STH->execute();
//Get Column Names for Header
$STMT = $DBH->query('SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = \'database\' AND TABLE_NAME = \'my_table\'');
$header = $STMT->fetchAll(PDO::FETCH_NUM);
//Export to .CSV
$fp = fopen('php://output', 'w');
fputcsv($fp,$header);
while ($row = $STH->fetch(PDO::FETCH_NUM)) fputcsv($fp,$row);
fclose($fp);
?>
2 回答
您不必查询information_schema .
只需将行作为关联数组获取并在输出数据之前输出键:
看起来问题实际上应该是“如何使用PDO获取表格的列名数组?”在另一个SO问题中找到 .
然后将数组转换为CSV .
这是另一种不是“实验性”的方式......
php pdo: get the columns name of a table