这个简单的加密和解密程序有什么问题？ [等候接听]

1 回答

• 1

  我读取你的代码非常有趣，因为前段时间我曾试图自己编写加密和解密 . 所以我想我知道你想要什么 .

  首先，Python字符串不喜欢assignements .

  So we convert the string to a list

  def enc(a):
     a = list(a)
  

  After that we look at your calls

  h=input()
  print(enc(h))
  print(dec(h))
  

  These calls will just produce some "random" strings, so I propose:

  h=input()
  h= enc(h)
  print(h)
  print(dec(h))
  

  这将加密字符串，而不是打印字符串 . 将其传递给dec方法，并在回滚enc中的更改后打印您输入的字符串 .

  At last but not least, we have to look at your dec method:

  else:
        m[i]=chr(ord(m[i]+5)
  

  如果你在enc中使用5，你将永远无法获得原始字符串，这应该是加密和解密中最重要的事情 .

  So you would have to change it to

  else:
        m[i]=chr(ord(m[i])-5)
  

  So if you change that all, the final code should look like that:

  def enc(a):
     a = list(a)
     for i in range(len(a)):
        if (i%2==0):
             a[i]=str(chr(ord(a[i])+3))
         else:
             a[i]=str(chr(ord(a[i])+5))
     r1 = ''.join(a)
     return r1
  
  def dec(m):
      m = list(m)
      for i in range(len(m)):
          if (i%2==0):
              m[i]=str(chr(ord(m[i])-3))
          else:
              m[i]=str(chr(ord(m[i])-5))
      string2 = "".join(m)
      return string2
  
  
  h = "Hallo"
  h = enc(h)
  print(h)
  print(dec(h))
  

  因此，对于字符串“Welcome to StackOverflow”，输出将为：

  after enc: Zjohrrh%wt#XwffpR{hwiqr|
  after dec: Welcome to StackOverflow
  

  回复于 2024-04-25T08:40:57+08:00