程序显示所有签名的短号码-Java 学习之路

*编辑：我错误地删除了我写的关于使用short＆char的评论在现代编程中有点过时/不高效 . 这个只是练习基本的东西 . **

该程序创建并打印一系列带符号的短值，从无效的短“空格/世界”中的等价物开始，从值0开始 .

**示例：在短16位的机器上：
unsigned short：0 1 2 .... 65535
=>签名短：0 1 2 ... 32766 -32767 -32766 -32765 ... -2 -1

#include <stdio.h>
#include <stdlib.h>
#include <limits.h>

//Initialize memory pointed by p with values 0 1 ... n
//Assumption : the value of n can be converted to 
//             short int (without over/under-flow)
unsigned int initArr (short int *p, unsigned int n);

int main (void)
{
  const unsigned int lastNumInSeq = USHRT_MAX;
  short *p_arr = (short *) malloc ( (lastNumInSeq + 1) * sizeof (short));
  short int lastValSet = initArr (p_arr, lastNumInSeq); //returns the "max" val written

//  for (unsigned i = 0; i < numOfElem; i++)
//      printf ("[%d]=%d \n", i, (*(p_arr + i)));

  printf ("lastValSet = %d *(p_arr + lastNumInSeq) = %d  ",
           lastValSet,*(p_arr + lastNumInSeq ));

  return 0;
}

unsigned int initArr (short *p, unsigned int n)
{
  unsigned int offset,index = 0;

  while (index <= n){
      offset = index;
      *(p + offset) = ++index -1 ;
  }

  return offset;

1 回答

还需要一些其他的清理工作 .

函数签名应该改变

short initArr (short *p, unsigned int n);

至

unsigned int initArr (short *p, unsigned int n);

变量'lastValSet'应该将其类型更改为unsigned int .

这条评论也令人困惑：

//Assumption : the value of n can be converted to 
    //             short int (without over/under-flow)

它应该是这样的：

//Assumption : the value of n which is of type int can be converted to 
    //             short int (without over/under-flow) up to 32767 which is the 
    //             max value for a variable of short type.

回复于 2024-05-19T04:43:57+08:00

程序显示所有签名的短号码

1 回答

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