来自ZipInputStream的ZipEntry的getInputStream（不使用ZipFile类）

3 回答

• 18

  它以这种方式工作

  static InputStream getInputStream(File zip, String entry) throws IOException {
      ZipInputStream zin = new ZipInputStream(new FileInputStream(zip));
      for (ZipEntry e; (e = zin.getNextEntry()) != null;) {
          if (e.getName().equals(entry)) {
              return zin;
          }
      }
      throw new EOFException("Cannot find " + entry);
  }
  
  public static void main(String[] args) throws Exception {
      InputStream in = getInputStream(new File("f:/1.zip"), "launch4j/LICENSE.txt");
      Scanner sc = new Scanner(in);
      while(sc.hasNextLine()) {
          System.out.println(sc.nextLine());
      }
      in.close();
  }
  

  回复于 2024-05-04T09:10:26+08:00
• 16

  呃， ZipInputStream 已经 InputStream. 你不需要另一个 . 获取下一个 ZipEntry 将流放在条目的开头 . 见Javadoc .

  回复于 2024-05-04T09:10:26+08:00
• 0

  要返回稍后可以使用的输入流列表，我使用了以下内容

  public static List<InputStream> listResourcesInJar(URL jar) throws IOException{
      ZipInputStream zipInputStream = new ZipInputStream(jar.openStream());
      ZipEntry zipEntry = null;
  
      List<InputStream> inputStreams = new ArrayList<>();
  
      while ((zipEntry = zipInputStream.getNextEntry()) != null) {
          String entryName = zipEntry.getName();
          if (entryName.endsWith(".xsd")) {
              inputStreams.add(convertToInputStream(zipInputStream));
          }
      }
      return inputStreams;
  }
  
  private static InputStream convertToInputStream(final ZipInputStream inputStreamIn) throws IOException {
      ByteArrayOutputStream out = new ByteArrayOutputStream();
      IOUtils.copy(inputStreamIn, out);
      return new ByteArrayInputStream(out.toByteArray());
  }
  

  回复于 2024-05-04T09:10:26+08:00