使用LibreOffice Basic处理矩阵(LibreOffice Calc)

我将在 4 × 6 (代码中的m×n)矩阵的每个单元格上使用以下公式来获得规范化矩阵:

\pi_=\frac{x_}{\sqrt{\Sigma_^m x_^2}}

Calc中的矩阵是:

enter image description here

我在LibreOffice中使用以下基本代码:

REM  *****  BASIC  *****

Sub Main

Normalize(5,3)

End Sub



Sub Normalize (ByVal n As Integer,ByVal m As Integer)

Dim Doc As Object
Dim Sheet As Object
Dim SrcCell 'Cell in the source matrix 
Dim TargetCell 'Cell in the target matrix where normalized values are saved 
Dim TempCell As Object 

Dim I 'index 
Dim J 'index 
Dim JJ 'inner index 
Dim Sum 'Sigma x_ij^2 (j=0 to m)
Dim m 'maximum row index 
Dim n 'maximum column index 


Doc = ThisComponent
Sheet = Doc.Sheets(0)




For I = 0 to n  'traverse columns 
    For J=0 to m 'traverse rows 
        SrcCell = Sheet.getCellByPosition(I,J)
        'Now apply the normalization formula for this cell 
        'Run a new loop to run formula on this cell 
        Sum = 0 'Reset Sum to 0
        For JJ=0 to m 
            TempCell = Sheet.getCellByPosition(I,JJ)
            Sum = Sum + (TempCell.Value^2)
        Next 
        TargetCell = Sheet.getCellByPosition(I+n+1,J) 'Place the normalized cells in a new matrix cell, n+1 cells away

        'Put the sum in the formula 
        TargetCell.Value = SrcCell.Value/Sqr(Sum)

    Next 


Next 

End Sub

我希望规范化矩阵出现在原始矩阵的右侧 . 但没有出现 . 我究竟做错了什么?

回答(1)

2 years ago

该代码使用 nm 作为参数,但随后声明它们,销毁这些值 . 要修复,请删除以下两行 . 为便于阅读,请将这些注释移至 Sub Normalize 附近 .

Dim m 'maximum row index 
Dim n 'maximum column index

要使用Basic IDE调试器查找此类问题,请在工具栏中按Breakpoint On / Off以设置几个断点,并启用Watch .