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柏林噪音 - 我做错了什么?

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我刚刚开始世界一代,我一直在寻找perlin noise的教程,但遗憾的是谷歌上没有很多东西可以找到 . 我遵循教程的最后几天,但我无法让我的代码工作 .

这是我的Java方法 .

private static double[][] createNoise(int xn, int yn, int sps) {
    int m = yn * sps;
    int n = xn * sps;
    double[][] u = new double[yn + 1][];
    double[][] v = new double[yn + 1][];

    double[][] x = new double[m][];
    double[][] y = new double[m][];
    double[][] z = new double[m][];

    for (int i = 0; i < m; i++) {
        x[i] = new double[n];
        y[i] = new double[n];
        z[i] = new double[n];
    }
    for (int i = 0; i < yn + 1; i++) {
        u[i] = new double[xn + 1];
        v[i] = new double[xn + 1];
    }

    for (int i = 0; i < xn + 1; i++) {
        for (int j = 0; j < yn + 1; j++) {
            u[i][j] = nextRandom();
            v[i][j] = nextRandom();
        }
    }
    double hx = xn / (n - 1);
    double hy = yn / (m - 1);
    for (int i = 0; i < m; i++) {
        for (int j = 0; j < n; j++) {
            x[i][j] = hx * j;
            y[i][j] = hy * i;
        }
    }

    for (int i = 0; i < m; i++) {
        for (int j = 0; j < n; j++) {
            int xc = (int)x[i][j];
            int yc = (int)y[i][j];

            if (x[i][j] % 1 == 0 && x[i][j] != 0 ) xc = xc - 1;
            if (y[i][j] % 1 == 0 && y[i][j] != 0 ) yc = yc - 1;

            double xr = x[i][j] - xc;
            double yr = y[i][j] - yc;
            double s11[] = {-xr, -yr};
            double s21[] = {-xr, 1 - yr};
            double s22[] = {1 - xr, 1 - yr};
            double s12[] = {1 - xr, -yr};

            double q11 = s11[0] * u[yc][xc] + s11[1] * v[yc][xc];
            double q21 = s21[0] * u[yc + 1][xc] + s21[1] * v[yc + 1][xc];
            double q22 = s22[0] * u[yc + 1][xc + 1] + s22[1] * v[yc + 1][xc + 1];
            double q12 = s12[0] * u[yc][xc + 1] + s12[1] * v[yc][xc + 1];

            z[i][j] = lerp(x[i][j], y[i][j], xc, xc + 1, yc, yc + 1, q11, q12, q21, q22);
        }
    }

    return z;
}

该方法遗留下来的高度图看起来像这样

enter image description here

如您所见,第一行/列正在运行,但之后算法似乎失败了 . 我确定了方法

nextRandom();

返回介于-1和1之间的浮点值 .

非常感谢!

1 回答

  • 1

    感谢用户@gawi指出这一点 .

    hx = xn / (n - 1);
    

    将除以2个整数,并且很可能返回0.您可以通过向其转换双精度来解决此问题:

    double hx = (double)xn / (n - 1);
    

    Then the map just works!

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