找出三角形是正确的，锐角还是钝角

2 回答

• 2

  我已经简化了你的代码，首先找到最长的一面，并删除大部分的比较（和括号） .

  但最重要的是，你的急性和钝角的方形比较是错误的 . 对于急性三角形，较小边的正方形的总和大于最长的正方形的总和 .

  #include <stdio.h>
  #include <stdlib.h>
  #include <math.h>
  
  //Program that calculates the type of triangle
  int main(int argc, char *argv[]) {
  
      int x,y,z,longest;
  
      printf("Type in the integer lengths of 3 sides of a triangle:\n");
      scanf("%d %d %d", &x, &y, &z); //reads the user's inputs
      if((x<=0) || (y<=0) || (z<=0)) {
        printf("This is not a triangle.\n");
      } else {
          if((x + y <= z) || (x + z <= y) || (y + z <= x)) {
          printf("This is not a triangle.\n");
          } else {
  
              longest = z;
              if (longest < x) {
                  z = longest;
                  longest = x;
                  x = z;
              }
              if (longest < y) {
                  z = longest;
                  longest = y;
                  y = z;
              }
  
              if( x * x + y * y == longest * longest ) {
                  printf("This is a right-angled triangle.\n");
              } else if( x * x + y * y > longest * longest) {
                  printf("This is an acute-angled triangle.\n");
              } else printf("This is an obtuse-angled triangle.\n");
          }
    }
  
    return 0;
  }
  

  回复于 2024-05-04T03:49:36+08:00
• 0

  对于边a，b，c的三角形：

  为锐角：a ^ 2 b ^ 2> c ^ 2和b ^ 2 c ^ 2> a ^ 2和c ^ 2 a ^ 2> b ^ 2 .

  为钝角：a ^ 2 b ^ 2 <c ^ 2或b ^ 2 c ^ 2 <a ^ 2或c ^ 2 a ^ 2> b ^ 2 .

  回复于 2024-05-04T03:49:36+08:00