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正则表达式24小时unix时间戳[关闭]

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我想创建一个24小时unix时间戳的正则表达式,例如: 01/01/2015 00:00:00 **(1420066800)** to 01/01/2015 23:59:59 **(1420153199)** ,相差86399秒 . 在unix时间戳格式中 .

我正在使用 range_regex python lib,但它对于如此巨大的范围来说是错误的 . range_to_pattern 方法( range_to_pattern(1420066800, 1420153199) )将生成一个正则表达式: 1420[0-1][5-6][3-6][1-8]\\d{2} 这对于创建正则表达式的静态边界是好的,但是当涉及到如下值时: 1420159111 ,因为左边的7位数(9)不在第三个范围内小组([3-6]) .

有人可以提供更好的python3 lib或解决方法如何创建86400秒的正则表达式 . 一天?

2 回答

  • 1

    根据我上面的评论,您正在使用该库中的错误功能 .

    您应该使用以下内容:

    range_to_regex(1420066800, 1420153199)
    

    这将返回正确的正则表达式:

    142006680\d|14200668[1-9]\d|14200669\d{2}|142006[7-9]\d{3}|14200[7-9]\d{4}|14201[0-4]\d{4}|142015[0-2]\d{3}|1420153[0-1]\d{2}
    
  • 1
    # coding=utf8
    # the above tag defines encoding for this document and is for Python 2.x compatibility
    
    import re
    
    regex = r"1420([0]([6]([6]([8]([0][0-9])|[9][0-9]{2})|[7-9][0-9]{3})|[7-9][0-9]{4})|[1]([5]([3]([1]([9][0-9]|[0-8][0-9]{1})|[0][0-9]{2})|[0-2][0-9]{3})|[0-4][0-9]{4}))"
    
    test_str = ("01/01/2015 00:00:00 (1420066800) до 01/01/2015 23:59:59 (1420153199)\n\n"
        "1420016799     -no\n"
        "1420066799     -no\n"
        "1420066800     -yes\n"
        "1420066801     -yes\n"
        "1420067820     -yes\n"
        "1420067920     -yes\n"
        "1420073199     -yes\n"
        "1420103199     -yes\n"
        "1420152191     -yes\n"
        "1420153181     -yes\n"
        "1420153199     -yes\n"
        "1420153200     -no\n"
        "1420163199     -no")
    
    matches = re.finditer(regex, test_str)
    
    for matchNum, match in enumerate(matches):
        matchNum = matchNum + 1
    
        print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
    
        for groupNum in range(0, len(match.groups())):
            groupNum = groupNum + 1
    
            print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
    
    # Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
    

    在线:https://regex101.com/r/blnST4/1

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