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Go:致命错误:所有goroutines都睡着了 - 僵局

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我有一个文本文件,里面只有一行文字 . 我想将所有这些单词分别存储在一个通道中,然后从通道中提取所有这些单词并逐个打印 . 我有以下代码:

func main() {
    f, _ := os.Open("D:\\input1.txt")
    scanner := bufio.NewScanner(f)
    file1chan := make(chan string)   
    for scanner.Scan() {
        line := scanner.Text()

        // Split the line on a space
        parts := strings.Fields(line)

        for i := range parts {   
            file1chan <- parts[i]
        }    
    }
    print(file1chan)
}

func print(in <-chan string) {
    for str := range in {
        fmt.Printf("%s\n", str)
    }
}

但是当我运行它时,我收到以下错误:

致命错误:所有goroutines都睡着了 - 僵局! goroutine 1 [chan send]:main.main()

我尝试在网上查找,但我仍然无法修复它 . 有人可以告诉我为什么会这样,以及如何解决这个问题?

谢谢!

1 回答

  • 4

    您的 file1chan 是无缓冲的,因此当您尝试向该通道发送值时,它会永久阻塞,等待某人获取值 .

    您需要启动一个新的goroutine,或者将通道缓冲并将其用作数组 . 这是与另一个goroutine的版本:

    func main() {
        f, _ := os.Open("D:\\input1.txt")
        scanner := bufio.NewScanner(f)
        file1chan := make(chan string)
        go func() { // start a new goroutine that sends strings down file1chan 
            for scanner.Scan() {
                line := scanner.Text()
    
                // Split the line on a space
                parts := strings.Fields(line)
    
                for i := range parts {
                    file1chan <- parts[i]
                }
            }
            close(file1chan)
        }()
        print(file1chan) // read strings from file1chan
    }
    
    func print(in <-chan string) {
        for str := range in {
            fmt.Printf("%s\n", str)
        }
    }
    

    这里是缓冲版本,只处理一个字符串:

    func main() {
        f, _ := os.Open("D:\\input1.txt")
        scanner := bufio.NewScanner(f)
        file1chan := make(chan string, 1) // buffer size of one
        for scanner.Scan() {
            line := scanner.Text()
    
            // Split the line on a space
            parts := strings.Fields(line)
    
            for i := range parts {
                file1chan <- parts[i]
            }
        }
        close(file1chan) // we're done sending to this channel now, so we close it.
        print(file1chan)
    }
    
    func print(in <-chan string) {
        for str := range in { // read all values until channel gets closed
            fmt.Printf("%s\n", str)
        }
    }
    

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