如何在javascript中从服务器迭代json响应值

3 回答

• 2

  使用Array map()方法将对象数组中的所有特定属性值转换为单个数组 .

  To fetch all the names into an single array from Employee_Names :

  var empNames = employee.Employee_Names.map(function(item) {
      return item.Name;
    });
  

  To fetch all the names into an single array from OTHER_Name :

  var otherNames = employee.OTHER_Name.map(function(item) {
      return item.Name;
    });
  

  Working Demo

  var employee = {
    "Employee_Names" : [
       {
          "BAR_RATING" : "0",
          "Name" : "anand",
          "Name_RATING" : "0",
          "PATTERN" : "Ln",
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "av",
          "Name_RATING" : "0",
          "PATTERN" : "FiLi",
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "books",
          "Name_RATING" : "0",
          "PATTERN" : "Ln",
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "kanagalu",
          "Name_RATING" : "0",
          "PATTERN" : null,
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "specialty-av",
          "Name_RATING" : "0",
          "PATTERN" : "Fn-Ln",
  
       }
    ],
    "FOUND_Name" : [ null ],
    "OTHER_Name" : [
       {
          "BAR_RATING" : "0",
          "Name" : "kindle-cs-support",
          "Name_RATING" : "0",
          "PATTERN" : null,
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "noreply-ops-jobs",
          "Name_RATING" : "0",
          "PATTERN" : null,
  
       }
    ]
    };
    
    var empNames = employee.Employee_Names.map(function(item) {
      return item.Name;
    });
    
    var otherNames = employee.OTHER_Name.map(function(item) {
      return item.Name;
    });  
    
    console.log("Employee Names", empNames);
    console.log("Other Names", otherNames);
  

  回复于 2024-04-30T00:10:55+08:00
• 1

  从Employee.Employee_Names数组中获取字段“name”中的所有值

  var resultArray = Employee.Employee_Names.map(function(a) {return a.Name;});
  

  resultArray将是 ["anand", "av", "books", "kanagalu", "specialty-av" ]

  回复于 2024-04-30T00:10:55+08:00
• 2

  如果我理解正确，这应该适合您的需要 .

  我们遍历 "Employee_Names" 个对象 .

  // ES6 code    
  var allNames = employee["Employee_Names"].map(bar => bar.Name);
  
  // pure javascript
  var allNames = [];
  for (i = 0; i < employee["Employee_Names"].length; i++) {
    var element = employee["Employee_Names"][i];
  
    // We push only name
    allNames.push( element.Name );
  
    // We push full json object
     //allNames.push( element );
  }
  

  现在我们使用 allNames 数组分配新的json密钥 .

  employee = Object.assign(employee, { "NEW_NAMES" : allNames });
  

  检查工作例子：

  var employee = {
    "Employee_Names" : [
       {
          "BAR_RATING" : "0",
          "Name" : "anand",
          "Name_RATING" : "0",
          "PATTERN" : "Ln",
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "av",
          "Name_RATING" : "0",
          "PATTERN" : "FiLi",
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "books",
          "Name_RATING" : "0",
          "PATTERN" : "Ln",
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "kanagalu",
          "Name_RATING" : "0",
          "PATTERN" : null,
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "specialty-av",
          "Name_RATING" : "0",
          "PATTERN" : "Fn-Ln",
  
       }
    ],
    "FOUND_Name" : [ ],
    "OTHER_Name" : [
       {
          "BAR_RATING" : "0",
          "Name" : "kindle-cs-support",
          "Name_RATING" : "0",
          "PATTERN" : null,
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "noreply-ops-jobs",
          "Name_RATING" : "0",
          "PATTERN" : null,
  
       }
    ],
    "PERSONAL_Name" : [  ],
    "PROJECTED_Name" : [
       {
          "BAR_RATING" : "0",
          "Name" : "anand.venkatesan",
          "Name_RATING" : "0",
          "PATTERN" : "Fn.Ln",
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "anandv",
          "Name_RATING" : "0",
          "PATTERN" : "FnLi",
  
       },
       {
          "BAR_RATING" : "0",
          "Name" : "vanand",
          "Name_RATING" : "0",
          "PATTERN" : "LiFn",
  
       }
    ]
    };
  
  
  // ES6
  //var allNames = employee["Employee_Names"].map(bar => bar.Name);
  
  // pure javascript
  var allNames = [];
  for (i = 0; i < employee["Employee_Names"].length; i++) {
    var element = employee["Employee_Names"][i];
  
    // We push only name
    allNames.push( element.Name );
    
    // We push full json object
     //allNames.push( element );
  }
  
  // Now we assign new json key with our names
  employee = Object.assign(employee, { "NEW_NAMES" : allNames });
  
  // Our new employee json
  console.log(employee);
  

  回复于 2024-04-30T00:10:55+08:00