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获得所有独特的变化

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这是我有的课程：

public class Schedule
{
    public string mintime { get; set; }
    public string maxtime { get; set; }
    public string weekday { get; set; }
}

我得到了一份重复工作日的时间表清单

List<Schedule> list = new List<Schedule> {
    new Schedule { mintime = "01.01.2012", maxtime = "05.01.2012", weekday = "1" },
    new Schedule { mintime = "05.01.2012", maxtime = "10.01.2012", weekday = "1" },
    new Schedule { mintime = "10.01.2012", maxtime = "20.01.2012", weekday = "2" },
    new Schedule { mintime = "01.02.2012", maxtime = "10.02.2012", weekday = "2" },
    new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" },
    new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" }
};

如何使用以下所有组合获取List>：

List<List<Schedule>> list = new List<List<Schedule>> {
    new List<Schedule> { 
        new Schedule { mintime = "01.01.2012", maxtime = "05.01.2012", weekday = "1" },
        new Schedule { mintime = "10.01.2012", maxtime = "20.01.2012", weekday = "2" }, 
        new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" },
        new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" }
    },
    new List<Schedule> { 
        new Schedule { mintime = "01.01.2012", maxtime = "05.01.2012", weekday = "1" },
        new Schedule { mintime = "01.02.2012", maxtime = "10.02.2012", weekday = "2" },
        new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" },
        new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" }
    },
    new List<Schedule> { 
        new Schedule { mintime = "05.01.2012", maxtime = "10.01.2012", weekday = "1" },
        new Schedule { mintime = "10.01.2012", maxtime = "20.01.2012", weekday = "2" },
        new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" },
        new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" }
    },
    new List<Schedule> { 
        new Schedule { mintime = "05.01.2012", maxtime = "10.01.2012", weekday = "1" },
        new Schedule { mintime = "01.02.2012", maxtime = "10.02.2012", weekday = "2" },
        new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" },
        new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" }
    },
};

？

是否可以使用LINQ获取它？

我的问题的主要议题是 Build 时间表列表 . 每个时间表应包括星期一，星期二，星期三，星期四，星期五，星期六和星期日一次 . 我需要使用一个更常见的列表来构建这样的列表，该列表包含星期一，星期三等的许多时间表 .

c# .net linq math

1 回答

  • 2

    使用 Eric Lippert 的CartesianProduct here

    List<List<Schedule>> newList = CartesianProduct(list.GroupBy(l => l.weekday))
                               .Select(x => x.ToList())
                               .ToList();

    public static IEnumerable<IEnumerable<T>> CartesianProduct<T>(IEnumerable<IEnumerable<T>> sequences)
{
    IEnumerable<IEnumerable<T>> emptyProduct = new[] { Enumerable.Empty<T>() };
    return sequences.Aggregate(
        emptyProduct,
        (accumulator, sequence) =>
        from accseq in accumulator
        from item in sequence
        select accseq.Concat(new[] { item }));
}
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