[Android]对象无法强制转换为java.lang.String Asynctask-Java 学习之路

我坚持这个错误 .

java.lang.ClassCastException：java.lang.Object []无法强制转换为java.lang.String []

这是完整的代码 .

`protected void onCreate（Bundle savedInstanceState）{super.onCreate（savedInstanceState）;的setContentView（R.layout.activity_main）;

edTenDangNhap =(EditText) findViewById(R.id.edTenDangNhap);
    edMatKhau =(EditText) findViewById(R.id.edMatKhau);
    btnDangKi =(Button) findViewById(R.id.btnDangKi);
    btnDangNhap =(Button) findViewById(R.id.btnDangNhap);

    btnDangNhap.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            String tentk = edTenDangNhap.getText().toString();
            String matkhau = edMatKhau.getText().toString();

            // ==== I execute AsyncTask there
            AsyncTask dangnhap = new AsyncDangNhap();
            dangnhap.execute(tentk,matkhau); // IDE announce there : JDK 5.0 only.  Unchecked to call execute Params ...
        }
    });
}
public class AsyncDangNhap extends AsyncTask<String[], Void, Integer>{//error there
    @Override
    protected Integer doInBackground(String[]... params) {
        WebService sv = new WebService();
        int kiemtra = sv.KiemTraDangNhap(params[0],params[1]);
        return kiemtra;
    }
    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        Toast.makeText(getApplicationContext(),"Dang xu li ... !",Toast.LENGTH_LONG).show();
    }
    @Override
    protected void onPostExecute(Integer result) {
        super.onPostExecute(result);
        if(result >0){
            //Dang nhap thanh cong
            Toast.makeText(getApplicationContext(),"Dang nhap thanh cong !",Toast.LENGTH_LONG).show();
        }else{
            Toast.makeText(getApplicationContext(),"Dang nhap that bai !",Toast.LENGTH_LONG).show();
        }
    }
}`

1 回答

1
在 AsyncTask 和 doInBackground 方法中将 String[] 更改为 String ，因为当前在 dangnhap.execute 方法中传递字符串而不是String Array.like：
```
public class AsyncDangNhap extends AsyncTask<String, Void, Integer>{ 
    @Override
    protected Integer doInBackground(String... params) {
         .....
    }

  ....
}
```
回复于 2024-04-28T03:43:01+08:00

[Android]对象无法强制转换为java.lang.String Asynctask

1 回答

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