如何从地址中找到经度和纬度？-Java 学习之路

我想在Google Map 中显示地址的位置 .

如何使用Google Maps API获取地址的纬度和经度？

7 回答

123

这是您可以找到我们点击 Map 的纬度和经度的方法 .

public boolean onTouchEvent(MotionEvent event, MapView mapView) 
{   
    //---when user lifts his finger---
    if (event.getAction() == 1) 
    {                
        GeoPoint p = mapView.getProjection().fromPixels(
            (int) event.getX(),
            (int) event.getY());

        Toast.makeText(getBaseContext(), 
             p.getLatitudeE6() / 1E6 + "," + 
             p.getLongitudeE6() /1E6 , 
             Toast.LENGTH_SHORT).show();
    }                            
    return false;
}

它运作良好 .

要获取位置的地址，我们可以使用地理编码器类 .

回复于 2024-04-27T08:16:17+08:00

3
以上Kandha问题的答案：

它抛出“java.io.IOException服务不可用”我已经给了这些权限并包含了库...我可以获得 Map 视图...它会在地理编码器中抛出IOException ...

我在尝试后添加了一个catch IOException，它解决了问题
```
catch(IOException ioEx){
        return null;
    }
```
回复于 2024-04-27T08:16:17+08:00

public GeoPoint getLocationFromAddress(String strAddress){

Geocoder coder = new Geocoder(this);
List<Address> address;
GeoPoint p1 = null;

try {
    address = coder.getFromLocationName(strAddress,5);
    if (address==null) {
       return null;
    }
    Address location=address.get(0);
    location.getLatitude();
    location.getLongitude();

    p1 = new GeoPoint((double) (location.getLatitude() * 1E6),
                      (double) (location.getLongitude() * 1E6));

    return p1;
    }
}

strAddress 是包含地址的字符串 . address 变量保存转换后的地址 .

回复于 2024-04-27T08:16:17+08:00

Ud_an的解决方案包含更新的API

Note ：LatLng class是Google Play服务的一部分 .

Mandatory ：

<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>

<uses-permission android:name="android.permission.INTERNET"/>

Update: 如果您有目标SDK 23及更高版本，请确保您负责位置的运行时权限 .

public LatLng getLocationFromAddress(Context context,String strAddress) {

    Geocoder coder = new Geocoder(context);
    List<Address> address;
    LatLng p1 = null;

    try {
        // May throw an IOException
        address = coder.getFromLocationName(strAddress, 5);
        if (address == null) {
            return null;
        }

        Address location = address.get(0);
        p1 = new LatLng(location.getLatitude(), location.getLongitude() );

    } catch (IOException ex) {

        ex.printStackTrace();
    }

    return p1;
}

回复于 2024-04-27T08:16:17+08:00

如果您想将地址放在谷歌 Map 中，那么可以轻松使用以下内容

Intent searchAddress = new  Intent(Intent.ACTION_VIEW,Uri.parse("geo:0,0?q="+address));
startActivity(searchAddress);

要么

如果你需要从你的地址获得lat，那么请使用 Google Place Api

创建一个方法，返回 JSONObject ，其响应为 HTTP Call ，如下所示

public static JSONObject getLocationInfo(String address) {
        StringBuilder stringBuilder = new StringBuilder();
        try {

        address = address.replaceAll(" ","%20");    

        HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false");
        HttpClient client = new DefaultHttpClient();
        HttpResponse response;
        stringBuilder = new StringBuilder();


            response = client.execute(httppost);
            HttpEntity entity = response.getEntity();
            InputStream stream = entity.getContent();
            int b;
            while ((b = stream.read()) != -1) {
                stringBuilder.append((char) b);
            }
        } catch (ClientProtocolException e) {
        } catch (IOException e) {
        }

        JSONObject jsonObject = new JSONObject();
        try {
            jsonObject = new JSONObject(stringBuilder.toString());
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        return jsonObject;
    }

现在将 JSONObject 传递给getLatLong（）方法，如下所示

public static boolean getLatLong(JSONObject jsonObject) {

        try {

            longitute = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
                .getJSONObject("geometry").getJSONObject("location")
                .getDouble("lng");

            latitude = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
                .getJSONObject("geometry").getJSONObject("location")
                .getDouble("lat");

        } catch (JSONException e) {
            return false;

        }

        return true;
    }

我希望这对你和其他人有帮助.. !!谢谢..！！

回复于 2024-04-27T08:16:17+08:00

以下代码适用于google apiv2：

public void convertAddress() {
    if (address != null && !address.isEmpty()) {
        try {
            List<Address> addressList = geoCoder.getFromLocationName(address, 1);
            if (addressList != null && addressList.size() > 0) {
                double lat = addressList.get(0).getLatitude();
                double lng = addressList.get(0).getLongitude();
            }
        } catch (Exception e) {
            e.printStackTrace();
        } // end catch
    } // end if
} // end convertAddress

其中address是要转换为LatLng的String（123 Testing Rd City State zip） .

回复于 2024-04-27T08:16:17+08:00

Geocoder coder = new Geocoder(this);
        List<Address> addresses;
        try {
            addresses = coder.getFromLocationName(address, 5);
            if (addresses == null) {
            }
            Address location = addresses.get(0);
            double lat = location.getLatitude();
            double lng = location.getLongitude();
            Log.i("Lat",""+lat);
            Log.i("Lng",""+lng);
            LatLng latLng = new LatLng(lat,lng);
            MarkerOptions markerOptions = new MarkerOptions();
            markerOptions.position(latLng);
            googleMap.addMarker(markerOptions);
            googleMap.animateCamera(CameraUpdateFactory.newLatLngZoom(latLng,12));
        } catch (IOException e) {
            e.printStackTrace();
        }

回复于 2024-04-27T08:16:17+08:00

如何从地址中找到经度和纬度？

7 回答

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