如何通过c从qml ListView获取当前模型索引？

1 回答

• 0

  I found a solution, but it's only a workaround and broke the immutable(const) system

  //int current_id; //defined in .h
  
  QHash<int, QByteArray> SqlTableModel::roleNames() const
  {
      QHash<int, QByteArray> result;
      int i, NEXT_USER_ROLE = Qt::UserRole + 1;
  
      //add sql fields names
      for(i = 0; i != record().count(); i++){
          result[NEXT_USER_ROLE + i] = record().fieldName(i).toUtf8();
      }
  
      //add property fields names
      auto meta = metaObject();
      for(int j = meta->propertyOffset(); j != meta->propertyCount(); j++ ){
          result[Qt::UserRole + i + j] = meta->property(j).name();
      }
      return result;
  }
  
  QVariant SqlTableModel::data(const QModelIndex &id, int role) const
  {
      int NEXT_USER_ROLE = Qt::UserRole + record().count();
      if(role >= NEXT_USER_ROLE){
          SqlTableModel * _this = const_cast<SqlTableModel*>(this);
          _this->current_id = id.row();
          return property(roleNames()[role]);
      }else{
          return QSqlTableModel::data(index(id.row(), role - Qt::UserRole - 1), Qt::DisplayRole);
      }
  }
  

  And now we can use something like this:

  main.qml

  Text{                 
     text: iconName                   
  }
  

  model.h

  Q_PROPERTY(QString iconName READ getIconName CONSTANT);
  
  QString getIconName()
  {
      return QSqlTableModel::data(index(current_id, 3), Qt::DisplayRole).toString();
  }
  

  回复于 2024-04-27T21:04:07+08:00