首页 文章

RegEx：匹配用单引号括起来的字符串，但不匹配双引号内的字符串

提问于
浏览 次
4

我想写一个正则表达式来匹配用单引号括起来的字符串，但是不应该匹配带有双引号的单引号的字符串 .

Example 1:

a = 'This is a single-quoted string';

a 的整个值应匹配，因为它用单引号括起来 .

编辑：完全匹配应该是： 'This is a single-quoted string'

Example 2:

x = "This is a 'String' with single quote";

x 不应返回任何匹配项，因为单引号位于双引号内 .

我试过 /'.*'/g 但它也匹配双引号字符串中的单引号字符串 .

Thanks for the help!

编辑：

使它更清楚

鉴于以下字符串：

The "quick 'brown' fox" jumps
over 'the lazy dog' near
"the 'riverbank'".

匹配应该只是：

'the lazy dog'
javascript regex string

3 回答

  • 6

    假设不必处理转义引号（这可能会使正则表达式复杂化），并且所有引号都是正确 balancer 的（没有像 It's... "Monty Python's Flying Circus"! 那样），那么你可以查找单引号字符串，后跟一个偶数双引号：

    /'[^'"]*'(?=(?:[^"]*"[^"]*")*[^"]*$)/g

    看到它live on regex101.com .

    Explanation:

    '        # Match a '
[^'"]*   # Match any number of characters except ' or "
'        # Match a '
(?=      # Assert that the following regex could match here:
 (?:     # Start of non-capturing group:
  [^"]*" # Any number of non-double quotes, then a quote.
  [^"]*" # The same thing again, ensuring an even number of quotes.
 )*      # Match this group any number of times, including zero.
 [^"]*   # Then match any number of characters except "
 $       # until the end of the string.
)        # (End of lookahead assertion)
    回复于
  • 0

    尝试这样的事情：

    ^[^"]*?('[^"]+?')[^"]*$

    现场演示

    回复于
  • 1

    如果你没有严格限制正则表达式，你可以使用函数“indexOf”来查明它是否是双引号匹配的子字符串：

    var a = "'This is a single-quoted string'";
var x = "\"This is a 'String' with single quote\"";

singlequoteonly(x);

function singlequoteonly(line){
    var single, double = "";
    if ( line.match(/\'(.+)\'/) != null ){
        single = line.match(/\'(.+)\'/)[1];
    }
    if( line.match(/\"(.+)\"/) != null ){
        double = line.match(/\"(.+)\"/)[1];
    }

    if( double.indexOf(single) == -1 ){
        alert(single + " is safe");
    }else{
        alert("Warning: Match [ " + single + " ] is in Line: [ " + double + " ]");
    }
}

    请参阅下面的JSFiddle：

    JSFiddle

    回复于

相关问题