ifstream打开由cin命名的文件，但不是从数组中提取的文件 . cin和常规字符串定义之间有什么区别吗？

TL; DR文件名存储为数组中的字符串（使用new） - ifstream不会打开它们（perror返回“No such file or directory”） . 通过调用用户来交换数组变量以命名文件（使用cin） - ifstream打开文件 . 为什么？如何让阵列工作？

Things to Know

• 所有文件都存在于命名方案run20 ### where的文件夹中

• 所有文件都命名为S20 ### . ABC其中###与父目录相同，ABC可以从001-999开始 . 这些都是ifstream和getline可以打开的文本文件（虽然没有.txt扩展名） .

我正在编写一个程序，它将从多达150个文件中提取信息 . 我写的早期版本让用户输入文件名（使用cin） . ifstream每次都获取存储的名称并成功打开文件 . 显然，我不想输入150个文件名，因此程序将所有文件名存储为数组中的字符串以供程序使用 . 但是，当它打开文件时（在正确的路径中并使用正确的文件名和扩展名），我从perror获得的错误将返回“No such file or directory” . 如果我只是快速交换变量，以便文件名来自cin，则文件打开 . 为什么cin工作和阵列版本没有？有没有办法让阵列工作？

我也尝试过类似没有数组的东西 . 相反，在将从数组中提取文件的for循环中，文件每次都会被命名 .

这是代码（抱歉 Headers ，无法正确格式化）：

#include <iostream>
#include <array>
#include <string>
#include <ctime>
#include <cstring>
#include <fstream>
#include <sstream>

using namespace std;

int main() {
//--------------------------Initial setup----------------------------------
    cout << "Please give the full name of the folder you would like to open in the /Users/lucas/HPS/TDCData directory" << endl << endl;
    string sFolderName;
    cin >> sFolderName;

    // Create path. I have mine here but you'll have to change it to something you'll 
    // use if you want to run the code
    string sPathName = "/Users/lucas/HPS/TDCData/" + sFolderName;

//----------------Create file name array------------------------------------    
    // Get naming base from the folder name given
    string sFileBase = "S20";
    for (int i = 5; i <= sFolderName.length(); i++){
            sFileBase = sFileBase + sFolderName[i];
    }

    //Specify range since different directories have different numbers of files
    cout << "Files must be named S20###.ABC" << endl;
    cout << "Specify a range for ABC" << endl;
    int iFloor;
    int iCeiling;
    cout << "Floor: " << endl;
    cin >> iFloor;
    cout << "Ceiling: " << endl;
    cin >> iCeiling;

    // Define an array to store names and then store them
    string *aFiles;
    int iFilesSize = iCeiling - iFloor + 1;
    aFiles = new string [iFilesSize];
    cout << "Array created" << endl;
    for (int i = iFloor; i <= iCeiling; i++){
        string name = sFileBase;
        if (i < 10){
            name = name + ".00" + to_string(i);
        }
        else if (i < 100) {
            name = name + ".0" + to_string(i);
        }
        else {
            name = name + '.' + to_string(i);
        }
        aFiles[i-1] = name;
    }

//----------------Open each file in aFiles----------------------
    for (int i = 0; i < iFilesSize; i++){
        // There are two important lines of code here. The first gets sFileName from
        // aFiles. The second gets sFileName from user input using cin (this is commented out). 
        // Obviously, none of the last section of code is needed for the second line to work.
        // The first line does not work for me. The second does.

        string sFileName;

        //First
        sFileName = aFiles[i];

        //Second
        //cin >> sFileName

        string sFullPath = sPathName + "/" + sFileName;
        cout << "Searching ... " << sFullPath << endl << endl;

        //Open file
        ifstream inputFile(sFullPath);

        //Check that the file opened
        if (! inputFile.is_open()) {
        cout << "Error reading" << sFullPath << endl;
            perror("Error is: ");
            return 0;
        }
        else {
            cout << "File opened successfully..." << aFiles[i] << endl << endl;
        }
    }
    cout << "All files opened..." << endl << endl;
    return 0;

}

另外here's链接到其中一个目录的zip，用于任何有人可能想要运行的测试 . 感谢您的帮助！