如何在Android中更改Drawable的颜色？-Java 学习之路

225

我正在开发一个Android应用程序，我有一个可绘制的，我正在从源图像加载 . 在这个图像上，我想将所有白色像素转换为不同的颜色，比如蓝色，然后缓存生成的Drawable对象，以便稍后使用 .

例如，假设我有一个20x20的PNG文件，中间有一个白色圆圈，圆圈外的所有内容都是透明的 . 将白色圆圈变为蓝色并缓存结果的最佳方法是什么？如果我想使用该源图像创建几个新的Drawables（比如蓝色，红色，绿色，橙色等），答案是否会改变？

我猜我想以某种方式使用ColorMatrix，但我不确定如何 .

18 回答

30

我想你实际上只能使用 Drawable.setColorFilter( 0xffff0000, Mode.MULTIPLY ) . 这会将白色像素设置为红色，但我认为它不会影响透明像素 .

见Drawable#setColorFilter

回复于 2024-04-29T03:20:56+08:00

136

尝试使用此代码：

ImageView lineColorCode = (ImageView)convertView.findViewById(R.id.line_color_code);
int color = Color.parseColor("#AE6118"); //The color u want             
lineColorCode.setColorFilter(color);

回复于 2024-04-29T03:20:56+08:00

15
我知道这个问题在Lollipop之前就已经问过了，但是我想在Android 5上添加一个很好的方法 . 你创建了一个xml drawable，它引用了原始的并绘制了tint，就像这样：
```
<?xml version="1.0" encoding="utf-8"?>
<bitmap
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:src="@drawable/ic_back"
    android:tint="@color/red_tint"/>
```
Check out my blog post on this for more information .
回复于 2024-04-29T03:20:56+08:00

如果您有一个纯色的drawable，并且您想将其更改为不同的纯色，则可以使用 ColorMatrixColorFilter . 透明度得以保留 .

int iColor = Color.parseColor(color);

int red   = (iColor & 0xFF0000) / 0xFFFF;
int green = (iColor & 0xFF00) / 0xFF;
int blue  = iColor & 0xFF;

float[] matrix = { 0, 0, 0, 0, red,
                   0, 0, 0, 0, green,
                   0, 0, 0, 0, blue,
                   0, 0, 0, 1, 0 };

ColorFilter colorFilter = new ColorMatrixColorFilter(matrix);
drawable.setColorFilter(colorFilter);

回复于 2024-04-29T03:20:56+08:00

195

新的支持v4为api 4带来了色彩 .

你可以这样做

public static Drawable setTint(Drawable d, int color) {
    Drawable wrappedDrawable = DrawableCompat.wrap(d);
    DrawableCompat.setTint(wrappedDrawable, color);
    return wrappedDrawable;
}

回复于 2024-04-29T03:20:56+08:00

您应该为所有API执行此操作：

Drawable myIcon = getResources().getDrawable( R.drawable.button ); 
ColorFilter filter = new LightingColorFilter( Color.BLACK, Color.BLACK);
myIcon.setColorFilter(filter);

回复于 2024-04-29T03:20:56+08:00

3

我还使用 ImageView 作为图标（在 ListView 或设置屏幕中） . 但我认为有更简单的方法可以做到这一点 .

使用 tint 更改所选图标的颜色叠加层 .

在xml中，

android：tint =“@ color / accent”android：src =“@ drawable / ic_event”

工作正常，因为它来自 AppCompat

回复于 2024-04-29T03:20:56+08:00

我能够使用以下代码执行此操作，该代码取自一个活动（布局非常简单，只包含一个ImageView，并且不在此处发布） .

private static final int[] FROM_COLOR = new int[]{49, 179, 110};
private static final int THRESHOLD = 3;

public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.test_colors);

    ImageView iv = (ImageView) findViewById(R.id.img);
    Drawable d = getResources().getDrawable(RES);
    iv.setImageDrawable(adjust(d));
}

private Drawable adjust(Drawable d)
{
    int to = Color.RED;

    //Need to copy to ensure that the bitmap is mutable.
    Bitmap src = ((BitmapDrawable) d).getBitmap();
    Bitmap bitmap = src.copy(Bitmap.Config.ARGB_8888, true);
    for(int x = 0;x < bitmap.getWidth();x++)
        for(int y = 0;y < bitmap.getHeight();y++)
            if(match(bitmap.getPixel(x, y))) 
                bitmap.setPixel(x, y, to);

    return new BitmapDrawable(bitmap);
}

private boolean match(int pixel)
{
    //There may be a better way to match, but I wanted to do a comparison ignoring
    //transparency, so I couldn't just do a direct integer compare.
    return Math.abs(Color.red(pixel) - FROM_COLOR[0]) < THRESHOLD &&
        Math.abs(Color.green(pixel) - FROM_COLOR[1]) < THRESHOLD &&
        Math.abs(Color.blue(pixel) - FROM_COLOR[2]) < THRESHOLD;
}

回复于 2024-04-29T03:20:56+08:00

在您的活动中，您可以使用单一颜色为PNG图像资源着色：

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    myColorTint();
    setContentView(R.layout.activity_main);
}

private void myColorTint() {
    int tint = Color.parseColor("#0000FF"); // R.color.blue;
    PorterDuff.Mode mode = PorterDuff.Mode.SRC_ATOP;
    // add your drawable resources you wish to tint to the drawables array...
    int drawables[] = { R.drawable.ic_action_edit, R.drawable.ic_action_refresh };
    for (int id : drawables) {
        Drawable icon = getResources().getDrawable(id);
        icon.setColorFilter(tint,mode);
    }
}

现在当你使用R.drawable . *时，它应该用所需的色调着色 . 如果你需要额外的颜色，那么你应该能够.mutate（）绘制 .

回复于 2024-04-29T03:20:56+08:00

You can solve it using Android support compat libraries. :)

// mutate to not share its state with any other drawable
 Drawable drawableWrap = DrawableCompat.wrap(drawable).mutate();
 DrawableCompat.setTint(drawableWrap, ContextCompat.getColor(getContext(), R.color.your_color))

回复于 2024-04-29T03:20:56+08:00

看看这个示例代码“ColorMatrixSample.java”

/*
 * Copyright (C) 2007 The Android Open Source Project
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

package com.example.android.apis.graphics;

import com.example.android.apis.R;

import android.app.Activity;
import android.content.Context;
import android.graphics.*;
import android.os.Bundle;
import android.view.KeyEvent;
import android.view.View;

public class ColorMatrixSample extends GraphicsActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(new SampleView(this));
    }

    private static class SampleView extends View {
        private Paint mPaint = new Paint(Paint.ANTI_ALIAS_FLAG);
        private ColorMatrix mCM = new ColorMatrix();
        private Bitmap mBitmap;
        private float mSaturation;
        private float mAngle;

        public SampleView(Context context) {
            super(context);

            mBitmap = BitmapFactory.decodeResource(context.getResources(),
                                                   R.drawable.balloons);
        }

        private static void setTranslate(ColorMatrix cm, float dr, float dg,
                                         float db, float da) {
            cm.set(new float[] {
                   2, 0, 0, 0, dr,
                   0, 2, 0, 0, dg,
                   0, 0, 2, 0, db,
                   0, 0, 0, 1, da });
        }

        private static void setContrast(ColorMatrix cm, float contrast) {
            float scale = contrast + 1.f;
               float translate = (-.5f * scale + .5f) * 255.f;
            cm.set(new float[] {
                   scale, 0, 0, 0, translate,
                   0, scale, 0, 0, translate,
                   0, 0, scale, 0, translate,
                   0, 0, 0, 1, 0 });
        }

        private static void setContrastTranslateOnly(ColorMatrix cm, float contrast) {
            float scale = contrast + 1.f;
               float translate = (-.5f * scale + .5f) * 255.f;
            cm.set(new float[] {
                   1, 0, 0, 0, translate,
                   0, 1, 0, 0, translate,
                   0, 0, 1, 0, translate,
                   0, 0, 0, 1, 0 });
        }

        private static void setContrastScaleOnly(ColorMatrix cm, float contrast) {
            float scale = contrast + 1.f;
               float translate = (-.5f * scale + .5f) * 255.f;
            cm.set(new float[] {
                   scale, 0, 0, 0, 0,
                   0, scale, 0, 0, 0,
                   0, 0, scale, 0, 0,
                   0, 0, 0, 1, 0 });
        }

        @Override protected void onDraw(Canvas canvas) {
            Paint paint = mPaint;
            float x = 20;
            float y = 20;

            canvas.drawColor(Color.WHITE);

            paint.setColorFilter(null);
            canvas.drawBitmap(mBitmap, x, y, paint);

            ColorMatrix cm = new ColorMatrix();

            mAngle += 2;
            if (mAngle > 180) {
                mAngle = 0;
            }

            //convert our animated angle [-180...180] to a contrast value of [-1..1]
            float contrast = mAngle / 180.f;

            setContrast(cm, contrast);
            paint.setColorFilter(new ColorMatrixColorFilter(cm));
            canvas.drawBitmap(mBitmap, x + mBitmap.getWidth() + 10, y, paint);

            setContrastScaleOnly(cm, contrast);
            paint.setColorFilter(new ColorMatrixColorFilter(cm));
            canvas.drawBitmap(mBitmap, x, y + mBitmap.getHeight() + 10, paint);

            setContrastTranslateOnly(cm, contrast);
            paint.setColorFilter(new ColorMatrixColorFilter(cm));
            canvas.drawBitmap(mBitmap, x, y + 2*(mBitmap.getHeight() + 10),
                              paint);

            invalidate();
        }
    }
}

如何在Android中更改Drawable的颜色？

18 回答

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