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Laravel从关系的关系表中获取数据并选择列?

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我有3张 table

Users Table

+----+-------+----------+
| id | email | password |
+----+-------+----------+
| 1  | 1     | John     |
+----+-------+----------+

user_details Table

+----+--------------------+------------+-----------+
| id | user_id [FK_users] | first_name | last_name |
+----+--------------------+------------+-----------+
| 1  | 1                  | John       | Kevin     |
+----+--------------------+------------+-----------+

Posts Table

+----+--------------------+----------+
| id | user_id [FK_users] | title    |
+----+--------------------+----------+
| 1  | 1                  | 1st Post |
+----+--------------------+----------+

现在我已经在模型中创建了所有关系,现在我可以通过下面的eloquent查询访问user_details表,它返回整个用户表和user_details表,但我只想从user_details表中选择first_name和last_name我该怎么做?

$posts= Post::with('city:id,name_en', 'user.userDetail')->where('id', $id)->get();

1 回答

  • 0

    这将获取所有'post'属性,'user' id ,'user_details' user_id, first_name, last_name

    $posts= Post::with([
        'city:id,name_en',
        'user' => function ($query) {
            $query->select('id');
        },
        'user.userDetail' => function($query) {
            $query->select(['user_id', 'first_name', 'last_name']);
        }
    ])->where('id', $id)->get();
    

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