我有基于Jersey 1.18.1的RESTful服务，我想通过Swagger显示我的API .
首先，我必须得到JSON . 我读了这条指令：Swagger Core Jersey 1.X Project Setup 1.5 . Swagger允许设置不同的配置方法，我决定使用自定义的Application子类 . 我一步一步地做了所有事情，但我无法获得我必须用于swagger-ui的JSON .
我做了什么：
我的自定义应用
@ApplicationPath("api/v1")
public class DiscountsApp extends Application{
public DiscountsApp() {
BeanConfig beanConfig = new BeanConfig();
beanConfig.setVersion("1.0.2");
beanConfig.setSchemes(new String[]{"http"});
beanConfig.setHost("localhost:8002");
beanConfig.setBasePath("swaggerapi");
beanConfig.setResourcePackage("alexiuscrow.diploma.endpoints");
beanConfig.setScan(true);
}
@Override
public Set<Class<?>> getClasses() {
Set<Class<?>> resources = new HashSet();
resources.add(ShopsResources.class);
//...
resources.add(com.wordnik.swagger.jaxrs.listing.ApiListingResource.class);
resources.add(com.wordnik.swagger.jaxrs.listing.SwaggerSerializers.class);
return resources;
}
}
ShopsResources
@Path("/shops")
@Api(value="/shops", description="Shops")
public class ShopsResources {
@GET
@Produces(MediaType.APPLICATION_JSON)
@ApiOperation(value = "List shops", httpMethod = "GET",
notes = "List nearest or locality shops",
response = Shops.class, responseContainer = "List")
public String getShops(
@ApiParam( value = "Radius", required = false)
@QueryParam("radius") String radiusParam,
@ApiParam( value = "Latitude", required = true)
@QueryParam("lat") String latParam,
@ApiParam( value = "Longitude", required = true)
@QueryParam("lng") String lngParam) throws SQLException{
//The list of Shops objects is serialized to string
//using the custom GSON serializer and I know
//that there is the better method of the solution of this task.
}
}
}
来自pom.xml的一些依赖项
<dependency>
<groupId>javax.ws.rs</groupId>
<artifactId>jsr311-api</artifactId>
<version>1.1.1</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>com.sun.jersey</groupId>
<artifactId>jersey-server</artifactId>
<version>1.18.1</version>
</dependency>
<dependency>
<groupId>com.sun.jersey</groupId>
<artifactId>jersey-servlet</artifactId>
<version>1.18.1</version>
</dependency>
<dependency>
<groupId>com.sun.jersey</groupId>
<artifactId>jersey-bundle</artifactId>
<version>1.18.1</version>
</dependency>
<dependency>
<groupId>com.wordnik</groupId>
<artifactId>swagger-jersey-jaxrs</artifactId>
<version>1.5.1-M2</version>
</dependency>
在将应用程序部署到Tomcat之后，我试图获得http://localhost:8002/swaggerapi但是我没有结果 .
我没有在我的应用程序的根目录中找到 swagger.json （ /tomcat8/webapps/app ） .
怎么了？
如何使用我的API获取JSON？
2 回答
我没有正确构建网址 .
正确：
http：// ： / / {path from
@ApplicationPath} /swagger.json就我而言：http://localhost:8080/app/api/v1/swagger.json
谢谢Ron .
添加一个为我工作的相对路径（这是使用.netcore 1.1）