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检查字符串是否包含python中的另一个字符串

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因此，我正在忙着制作基于交互式文本的游戏，用户可以用他/她自己的话输入答案 .

我写了一段代码来打印某些字符串，当用户输入某些单词但我无法使其工作 .

无论我输入什么，它总是打印“NOVA ENTERS THE SPACECRAFT”我做错了什么？

以下是我的代码段：

craft_cave = input(char_name + ": I should probably search the ship for supplies and explore this cave, which should I do first? ")

print("")

if "craft" or "Craft" or "ship" or "Ship" in craft_cave:
  print("NOVA ENTERS THE SPACECRAFT")
elif "cave" or "Cave" or "mountain" or "Mountain" in craft_cave:
  print("NOVA LOOKS AROUND THE CAVE")
else:
  print("Invalid answer")
python-3.x

4 回答

  • 2
    if "craft" or "Craft" or "ship" or "Ship" in craft_cave:

    被评估为

    if ("craft" or ("Craft" or ("ship" or ("Ship" in craft_cave) ) ) ):

    "craft" 首先被评估为布尔值，它给出 True ，所以我们有

    if (True or ("Craft" or ("ship" or ("Ship" in craft_cave) ) ) ):

    由于 True or x 始终为 True ，因此语句的计算结果为

    if True:

    所以第一个if条件总是计算为 True .

    您需要直接检查每个if条件中的每个单词

    spacecraft_keywords = ["craft", "Craft", "ship", "Ship"]
cave_keywords = ["cave", "Cave", "mountain", "Mountain"]

def contains_any(keywords, s):
    return any(keyword in s for keyword in keywords)

if contains_any(spacecraft_keywords, craft_cave):
    pass
elif contains_any(cave_keywords, craft_cave):
...
    回复于
  • 1

    你需要检查一下这些词 . 尝试以下方法：

    vehicle_words = ["craft", "Craft", "ship", "Ship"]
cave_words = ["cave", "Cave", "mountain", "Mountain"]
if any(w in craft_cave for w in vehicle_words):
    print("NOVA ENTERS THE SPACESHIP")
elif any(w in craft_cave for w in cave_words)
    print("NOVA LOOKS AROUND THE CAVE")
else:
    print("Invalid Answer")
    回复于
  • 0

    错误的条件，它检查 "craft" 的值是否为真，它是 . 你应该做这样的事情：

    if "craft" in craft_cave or "Craft" in craft_cave or "ship" in craft_cave or "Ship" in craft_cave:
    # continue

    更好的是：

    if any(map(lambda word: word in craft_cave, ("craft", "Craft", "ship", "Ship"))):
    # continue
    回复于
  • 0

    更简单的方法，将所有单词放在列表中

    craft_cave = input( ": I should probably search the ship for supplies and explore 
this cave, which should I do first? ")

print("")
list1 = ('craft', 'Craft', 'ship', 'Ship')
list2 = ('cave', 'Cave', 'mountain', 'Mountain')  

if any(word in craft_cave for word in list1):
   print("NOVA ENTERS THE SPACECRAFT")

elif any(word in craft_cave for word in list2):
   print("NOVA LOOKS AROUND THE CAVE")

else:
   print("invalid")
    回复于

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