我很新玩，开始使用Play 2.0 .
尝试在视图中使用jqgrid但无法显示数据，下面是代码：
控制器：
public static Result userLogs(String criteria) throws JSONException {
JSONObject responcedata = new JSONObject();
JSONArray logData = UserLogs.getUserlogs();
responcedata.put("page", 1);
responcedata.put("records", 10);
responcedata.put("rows", logData);
response().setContentType("application/json");
return ok(userlogs.render(responcedata));
}
型号类：
public static JSONArray getUserlogs（）{
String query = "select date from user where user_id=1 and resp=1";
List<SqlRow> userLogs = Ebean.createSqlQuery(query).findList();
JSONArray cellarray = new JSONArray();
int tableSize = userLogs.size();
int i = 0;
while (i < tableSize) {
JSONObject cellObj = new JSONObject();
JSONArray cell = new JSONArray();
cell.put(i + 1);
cell.put(userLogs.get(i).getTimestamp("date"));
try {
cellObj.put("cell", cell);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
cellarray.put(cellObj);
i++;
}
return cellarray;
}
观点：
jQuery的（ “＃格”） . jqGrid的（{
url:"@Application.userLogs(),
datatype : 'json',
colNames:['S.No','date'],
colModel:[
{name:'sno',index:'sno', width:50, sorttype:"int"},
{name:'date',index:'date', width:150, sorttype:"date"}
],
jsonReader : {
root: "rows",
page: "page",
total: "total",
records: "records",
cell: "cell",
loadOnce: "true",
id: "id",
userdata: "userdata"
},
width: 900,
height: 220,
rowNum:10, rowList:[10,20,30],
pager: '#pager',
sortname: 'id',
viewrecords: true,
gridview: true,
sortorder: "desc",
loadonce:true,
ignoreCase:true,
multiselect: true,
});
});
以下是例外::
play.api.Application $$ anon $ 1：执行异常[[RuntimeException：java.lang.StackOverflowError]] at play.api.Application $ class.handleError（Application.scala：289）〜[play_2.10.jar：2.1 . 1] at play.api.DefaultApplication.handleError（Application.scala：383）[play_2.10.jar：2.1.1] at play.core.server.netty.PlayDefaultUpstreamHandler $$ anon $ 2 $$ anonfun $ handle $ 1.apply （PlayDefaultUpstreamHandler.scala：144）[play_2.10.jar：2.1.1] at play.core.server.netty.PlayDefaultUpstreamHandler $$ anon $ 2 $$ anonfun $ handle $ 1.apply（PlayDefaultUpstreamHandler.scala：140）[play_2 . 10.jar：2.1.1]在play.api.libs的play.api.libs.concurrent.PlayPromise $$ anonfun $ extend1 $ 1.apply（Promise.scala：113）[play_2.10.jar：2.1.1] .concurrent.PlayPromise $$ anonfun $ extend1 $ 1.apply（Promise.scala：113）[play_2.10.jar：2.1.1] java.lang.RuntimeException：java.lang.StackOverflowError at play.libs.F $ Promise $ 6 .apply（F.java:401)~ [play_2.10.jar：2.1.1] at scala.concurrent.Future $$ anonfun $ map $ 1.liftedTree2 $ 1（Future.scala：253）〜[scala-library.jar ：na] a t scala.concurrent.Future $$ anonfun $ map $ 1.apply（Future.scala：249）〜[scala-library.jar：na] at scala.concurrent.Future $$ anonfun $ map $ 1.apply（Future.scala： 249）〜[scala-library.jar：na] at scala.concurrent.impl.CallbackRunnable.run（Promise.scala：29）〜[scala-library.jar：na] at akka.dispatch.BatchingExecutor $ Batch $$ anonfun $ run $ 1.liftedTree1 $ 1（BatchingExecutor.scala：67）〜[akka-actor_2.10.jar：na] java.lang.StackOverflowError：null at com.mysql.jdbc.Util.handleNewInstance（Util.java:431）〜 [mysql-connector-java-5.1.18.jar：na] at com.mysql.jdbc.PreparedStatement.getInstance（PreparedStatement.java:872）〜[mysql-connector-java-5.1.18.jar：na] at com .mysql.jdbc.ConnectionImpl.clientPrepareStatement（ConnectionImpl.java:1490）〜[mysql-connector-java-5.1.18.jar：na] at com.mysql.jdbc.ConnectionImpl.prepareStatement（ConnectionImpl.java:4253)~ [ mysql-connector-java-5.1.18.jar：na] at com.mysql.jdbc.ConnectionImpl.prepareStatement（ConnectionImpl.java:4152）〜[mysql-connector-java-5.1.18.jar：na] at com . jolbox.bonecp .ConnectionHandle.prepareStatement（ConnectionHandle.java:820)~ [bonecp.jar：0.7.1.RELEASE]
让我知道如何处理这种情况，并使用jqgrid在视图中显示列表 . 任何替代方法来实现这一点也有帮助 .
谢谢..！！！