Gradle / Jenkins：创建一个gradle文件以指向子项目

1 回答

• 1

  你可以在jenkins中制作三个版本，但除非需要单独构建库，否则它可能最终会付出额外的努力 . 听起来你真正想要的是一个多项目构建[1] . 一个简单的例子可以作为两个文件位于lib项目上方的文件夹中， build.gradle 和 settings.gradle

  settings.gradle 将定义构建范围中包含的项目 .

  例如，给定 project1 ， project2 和 project3 示例，您的 settings.gradle 可能如下所示 .

  rootProject.name = 'myRootProjectName'
  
  // note the name is not required to match the actual path
  include ":project1"
  // but if the name is not the same as the path then we can just
  // let gradle know where the project is expected
  project(":project1").projectDir = new File(settingsDir, "pathToProject1")
  
  include ":project2"
  project(":project2").projectDir = new File(settingsDir, "pathToProject2")
  
  include ":project3"
  project(":project3").projectDir = new File(settingsDir, "pathToProject3")
  
  //##### below would be instead of the code above, same thing just manual
  // project setup vs letting gradle find the subprojects
  // note sometimes you have lots of subprojects in that case it's sometimes
  // easier to just use a little logic for finding and setting up the subprojects.
  // don't use the code above ##### and below only use one or the other
  // or you will have errors.  The method below is the most scaleable since
  // adding projects requires zero modifications to the root project
  rootProject.name = 'myRootProjectName'
  
  // set up a couple file filters to find the dirs we consider subprojects
  FileFilter projectFilter = { File pathname ->
      FileFilter gradleProjectFilter = { File file -> file.name == 'build.gradle' }
      // add this folder if is a directory and that directory contains a build.gradle file
      // here note `File#listFiles` is true if it's `size() > 0` due to
      // groovy's concept of truth (details: http://groovy-lang.org/semantics.html#Groovy-Truth)
      return pathname.isDirectory() && pathname.listFiles(gradleProjectFilter)
  }
  
  settingsDir.listFiles(projectFilter).each { dir ->
      include ":$dir.name"
      project(":$dir.name").projectDir = dir
  }
  

  现在运行 gradle projects 任务应该显示三个子模块 .

  对于 build.gradle 文件，您可以根据需要为所有模块指定一些常用属性，或者只保留文件为空，它必须存在但可以为空 . 如果你想共享一些配置，那么你可以用这样的东西设置 build.gradle .

  project.subprojects { Project subproject ->
      // anything that is defined here will be executed before the subproject's build.gradle file
      subproject.buildscript {
          repositories {
              jcenter()
              // your private maven repo if needed
              maven { url 'http://1.2.3.4:8081/nexus/content/repositories/release' }
          }
          dependencies {
              // some plugin that is now available to be applied in any subproject
              classpath 'my.sweet.gradle:plugin:0.1'
          }
      }
      subproject.afterEvaluate {
          // this block is executed after the subproject's build.gradle file
          if (project.tasks.withType(org.gradle.jvm.tasks.Jar)) {
              // for example you might want to set the manifest for each subproject
              manifest {
                  attributes 'Implementation-Title': "Lib $subproject.name",
                          'Implementation-Version': version
              }
          }
      }
  }
  

  [1] https://docs.gradle.org/current/userguide/multi_project_builds.html

  回复于 2024-04-26T19:46:28+08:00