使用Symfony 3.4,我需要在注销前坚持用户,所以我实现了以下监听器:
<?php
namespace c975L\UserBundle\Listeners;
use Doctrine\ORM\EntityManagerInterface;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Http\Logout\LogoutHandlerInterface;
use c975L\UserBundle\Entity\User;
class LogoutListener implements LogoutHandlerInterface
{
private $em;
public function __construct(EntityManagerInterface $em)
{
$this->em = $em;
}
public function logout(Request $request, Response $response, TokenInterface $token)
{
$user = $token->getUser();
if ($user instanceof User) {
$user->setLatestSignout(new \DateTime());
$this->em->persist($user);
$this->em->flush();
}
}
}
我在 services.yml
自动装配
services:
_defaults:
autowire: true
autoconfigure: true
public: true
c975L\UserBundle\Listeners\:
resource: '../../Listeners/*'
但是我收到以下编译错误
编译错误:ContainerNxlf3ac \ appDevDebugProjectContainer :: load():无法打开所需的'/.../var/cache/dev/ContainerNxlf3ac/getLogoutlistener2Service.php'(include_path =' . :/ usr / share / php')
看起来我必须为服务添加别名但我无法做到这一点......
使用 parent::__construct();
时得到的结果相同
如果删除 __construct()
但未定义 $this->em
,则不会出现错误...
[EDIT - Added firewall part]
security.yml
firewalls:
dev:
pattern: ^/(_(profiler|wdt)|css|fonts|images|js)/
security: false
main:
pattern: ^/
provider: c975_l_userbundle
form_login:
login_path: user_signin
check_path: user_signin
default_target_path: user_dashboard
csrf_token_generator: security.csrf.token_manager
remember_me:
secret: '%secret%'
lifetime: 31536000
path: /
secure: true
anonymous: true
logout_on_user_change: true
logout:
path: user_signout
handlers: [c975L\UserBundle\Listeners\Logoutlistener]
1 回答
问题出在防火墙部分 . 使用"l"(小写)代替"L"(大写)
LogoutListener
名称是错误的 . 设置以下工作 .[EDIT] 有一个错误,已由https://github.com/symfony/symfony/pull/26355解决