首页 文章

C - 我输出数字和字母时输出有问题

提问于
浏览 次
0

我仍然是C和编程的新手，所以要温柔 .

给定圆心的中心和点，您可以使用此公式来查找圆的半径 . 编写一个程序，提示用户输入中心和圆上的一个点 . 然后程序应输出圆的半径，直径，周长和面积 . 您的程序必须至少具有以下功能：

calculateRadius：接收中心的x-y坐标并指向圆圈（由用户输入）并计算点之间的距离 . 该值作为圆的半径返回 .

calculateArea：接收圆的半径，计算并返回圆的面积 .

calculatePerimeter：接收圆的半径，计算并返回圆的周长 .

输出应清楚地显示结果圆的半径，面积和周长 .

这就是我到目前为止所给出的数字和字母作为输出 .

#include <iostream>
#include <cmath>
#define PI 3.141592

using namespace std;

int calculateRadius(float x1, float x2, float y1, float y2);
int calculateArea(float radius);
int calculatePerimeter(float radius);

int main()
{
    float x1;
    float x2;
    float y1;
    float y2;

    cout << "Please enter the first X Coordinate: " << endl;
    cin >> x1;
    cout << "Please enter the first Y Coordinate: " << endl;
    cin >> y1;

    cout << "Please enter the second X Coordinate: " << endl;
    cin >> x2;
    cout << "Please enter the second Y Coordinate: " << endl;
    cin >> y2;

    cout << "The radius of the circle is: " << calculateRadius << endl;
    cout << "The diameter of the circle is: " << endl;
    cout << "The cirfumference of the circle is: " << calculatePerimeter << endl;
    cout << "The area of the circle is: " << calculateArea << endl;

    system("pause");
    return 0;
}

int calculateRadius(float x1, float x2, float y1, float y2)
{
    float distance;
    float radius;

    distance = sqrt((pow(x2 - x1, 2)) + (pow(y2 - y1, 2)));

    radius = (distance / 2);

    return radius;
}

int calculateArea(float radius)
{
    float area;

    area = PI * pow(radius, 2);

    return area;
}

int calculatePerimeter(float radius)
{
    float perimeter;

    perimeter = 2 * PI * radius;

    return perimeter;
}
c++

2 回答

  • 0

    您需要指定函数的参数

    #include <iostream>
#include <cmath>
#define PI 3.141592

using namespace std;

int calculateRadius(float x1, float x2, float y1, float y2);
int calculateArea(float radius);
int calculatePerimeter(float radius);

int main()
{
    float x1;
    float x2;
    float y1;
    float y2;

    cout << "Please enter the first X Coordinate: " << endl;
    cin >> x1;
    cout << "Please enter the first Y Coordinate: " << endl;
    cin >> y1;

    cout << "Please enter the second X Coordinate: " << endl;
    cin >> x2;
    cout << "Please enter the second Y Coordinate: " << endl;
    cin >> y2;

    cout << "The radius of the circle is: " << calculateRadius(x1,x2,y1,y2) << endl;
    cout << "The diameter of the circle is: " << endl;
    cout << "The cirfumference of the circle is: " << calculatePerimeter(x1) << endl;
    cout << "The area of the circle is: " << calculateArea(x1) << endl;

    system("pause");
    return 0;
}

int calculateRadius(float x1, float x2, float y1, float y2)
{
    float distance;
    float radius;

    distance = sqrt((pow(x2 - x1, 2)) + (pow(y2 - y1, 2)));

    radius = (distance / 2);

    return radius;
}

int calculateArea(float radius)
{
    float area;

    area = PI * pow(radius, 2);

    return area;
}

int calculatePerimeter(float radius)
{
    float perimeter;

    perimeter = 2 * PI * radius;

    return perimeter;
}
    回复于
  • 0

    您还需要将函数的返回类型从int更改为float，因为您正在使用单精度 .

    回复于

相关问题