我正在将图像从Javascript上传到我的服务器,我的javascript是使用Phonegap创建的应用程序的客户端部分,它的作用是拍摄画廊的图片,我希望它能在服务器上收到,但我想我有一个类型的问题,因为在客户端中,图像被编码为ImageURI,我的控制器用Java开发,Spring-MVC接收MultiPartFile,我不知道如何在MultiPartFile中转换ImageURI来接收它 . 我留下我的密码Phonegap:

function getPhoto(source) {
      // Retrieve image file location from specified source
      navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50,
        destinationType: destinationType.FILE_URI,
        sourceType: source });
    }
    function onPhotoURISuccess(imageURI) {
        alert("Imagen URI subida");
      // Uncomment to view the image file URI
      // console.log(imageURI);

      // Get image handle
      //
      var largeImage = document.getElementById('largeImage');
  alert("Imagen URI subida 2");
      // Unhide image elements
      //
     // largeImage.style.display = 'block';
  alert("Imagen URI subida 3");
      // Show the captured photo
      // The inline CSS rules are used to resize the image
      //

    //  largeImage.src = imageURI;
         alert("Imagen URI subida 4");
       subirImagen(imageURI);

    }




      function subirImagen(fileURL) {
                alert("SUBIR IMAGEN"+ fileURL);
                    var options = new FileUploadOptions();
                    options.fileKey = "imagen";
                    options.fileName = fileURL.substr(fileURL.lastIndexOf('/') + 1);

                    var ft = new FileTransfer();
                    alert("UPLOAD");
                    ft.upload(fileURL, encodeURI("http://localhost:8080/HelloSpringMVC/fileUpload"), uploadSuccess, uploadFail, options);
                }

Servidor Java Spring -MVC:@RequestMapping(value =“/ uploadFile”,method = RequestMethod.POST)public @ResponseBody String uploadFileHandler(@RequestParam(“file”)MultipartFile file){System.out.println(“RECIBO ESTO”file ); String name =“tablero.png”;的System.out.println( “HOLA”); if(!file.isEmpty()){try {byte [] bytes = file.getBytes();

// Creating the directory to store file
            String rootPath = System.getProperty("catalina.home");
            File dir = new File(rootPath + File.separator + "tmpFiles");
                dir.mkdirs();

            // Create the file on server
            File serverFile = new File(dir.getAbsolutePath()+ File.separator + name);
            System.out.println("serverFile "+serverFile);
            BufferedOutputStream stream = new BufferedOutputStream(new FileOutputStream(serverFile));
            stream.write(bytes);
            stream.close();

            return "You successfully uploaded file=" + name;
        } catch (Exception e) {
            return "You failed to upload " + name + " => " + e.getMessage();
        }
    } else {
        return "You failed to upload " + name
                + " because the file was empty.";
    }
}