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“太多的格式参数”警告

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#include <stdio.h>

#define N 11
enum {FALSE, TRUE};
typedef int adj_mat[N][N];

int path2(adj_mat A, int u, int v, int temp)
{
if(u == temp && A[u][v] == TRUE)
return TRUE;

if(A[u][v] == FALSE)
return path2(A, u-1, v, temp);

if(A[u][v] == TRUE)
return path2(A, N, u, temp);

return FALSE;
}

int path(adj_mat A, int u, int v)
{
return path2(A, N, v, u);
}



int main()
{

int arr[N][N]= {{0,1,1,1,0,0,0,0,0,0,0},{0,0,0,0,1,1,1,1,1,0,0},
{0,0,0,0,0,0,0,0,0,1,0},{0,0,0,0,0,0,0,0,0,0,1},{0,0,0,0,0,0,0,0,0,0,0},
{0,0,0,0,0,0,0,0,0,0,0},{0,0,0,0,0,0,0,0,0,0,0},{0,0,0,0,0,0,0,0,0,0,0},
{0,0,0,0,0,0,0,0,0,0,0},{0,0,0,0,0,0,0,0,0,0,0},{0,0,0,0,0,0,0,0,0,0,0}};
int u;
int v;
printf("please enter two numbers \n");
scanf("%d %d", &u, &v);
printf("The answer is %d" "\n", path(arr, u, v),".\n");
return 0;
}

程序需要检查在给定的表示树的11X11矩阵中是否存在2个给定索引（u，v）之间的路径 . 当我尝试在终端编译我得到这个massege：

adjacency.c：41：1：警告：格式[-Wformat-extra-args]的参数太多，除此之外，程序不起作用 . 如果我输入（1,8）它应该返回true但它返回false .

c matrix adjacency-matrix

1 回答

  • 4

    您的格式说明符 "The answer is %d""\n" 是一个参数，但是您传递了两个， path(arr, u, v) 和 ".\n" ：

    printf("The answer is %d" "\n", path(arr, u, v),".\n");

    大概你需要

    printf("The answer is %d.\n", path(arr, u, v));
    回复于

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