如何在typescript中的对象Array中获取特定值-Java 学习之路

我有一个对象数组，我用* ngfor循环并显示在ngdropdownmenu中 . 我选择一个并返回一个包含名称和操作的对象，并将其分配给字符串变量 . 我怎样才能在打字稿中获取所选对象的动作值？

//Typescript Code:
specificaction: string = "";
public finishActions = [
{ name: "blah", action: "blahblahblah" },
{ name: "blah", action: "blahblahblah" },
{ name: "blah", action: "blahblahblah" },
{ name: "blah", action: "blahblahblah" },
{ name: "blah", action: "blahblahblah" },
{ name: "", action: "" }
] 
finishAction(action: string) {
this.specificaction= action;
//I CAN NOT GET THE specification.action
console.log(this.specificaction.action);
 }

//HTML
<div ngbDropdownMenu aria-labelledby="dropdownBasic1">
  <button class="dropdown-item text-right" *ngFor="let action of 
finishActions" (click)="finishAction(action)">{{action.name}}</button>
</div>

1 回答

我会做这样的事情：

<div *ngFor="let finishAction of finishActions">
    <p>{{ finishAction.action }}</p>
</div>

回复于 2024-05-11T02:30:04+08:00

如何在typescript中的对象Array中获取特定值

1 回答

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