UIDatePicker设置最小和最大小时

4 回答

• 1

  希望以下代码可以帮助您 .

  - (IBAction)dataPickerValueChanged:(UIDatePicker *)sender {
  
          NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:NSHourCalendarUnit fromDate:[testDatePicker date]];
  
  
          if ([dateComponents hour] > 8 && [dateComponents hour] < 22) {
              UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Error!" message:@"This time cant be selected" delegate:nil cancelButtonTitle:@"Dismiss" otherButtonTitles: nil];
              [alert show];
              return;
          }
  
           lblDate.text = [sender date];
  
      }
  

  回复于 2024-04-19T17:00:31+08:00
• 0

  NSDateComponents *components = [[NSCalendar currentCalendar] components:NSIntegerMax fromDate:self.datePicker.date];
  [components setHour:hour];
  [components setMinute:minutes];
  [components setSeconds:seconds];
  NSDate *date [[NSCalendar currentCalendar] dateFromComponents:components];
  self.datePicker.minimumDate = date;
  //same for maximumDate do this.
  

  回复于 2024-04-19T17:00:31+08:00
• 1

  您必须确保最短日期的时间是最长日期的上午8点和晚上10点 . NSDateFormatter将帮助您根据需要创建日期对象 .

  回复于 2024-04-19T17:00:31+08:00
• 0

  这适用于“时间模式”，否则选择的答案应该不直观地工作

  // minimum time
      components.hour = 0
      components.minute = 0
      let minTime = calendar.date(from: components)
  
      // max time
      components.hour = 23
      components.minute = 59
      let maxTime = calendar.date(from: components)
  
      // selected value current time or saved time
      let selectedDate = Date() // or saved time
      let nowComp = calendar.dateComponents([.hour, .minute], from: selectedDate)
      components.hour = nowComp.hour
      components.minute = nowComp.minute
      let selectedTime = calendar.date(from: components)!
  

  玩这些值并使用如下

  datePicker.datePickerMode = .time
      datePicker.date = selectedTime 
      datePicker.minimumDate = minTime 
      datePicker.maximumDate = maxTime
  

  回复于 2024-04-19T17:00:31+08:00