我想从DBPedia中提取5个电影(或电影)的人物 .
我的查询是:
ParameterizedSparqlString qs = new ParameterizedSparqlString(“”
"construct{?s ?p ?o}"“其中{?s a http://dbpedia.org/ontology/Film . "+ "?s?p?o "} OFFSET 0 LIMIT 5");
我得到以下结果:
1- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://dbpedia.org/ontology/Film .
2- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://www.w3.org/2002/07/owl#Thing .
3- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://www.wikidata.org/entity/Q386724 .
4- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://dbpedia.org/ontology/Wikidata:Q11424 .
5- http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham http://www.w3.org/1999/02/22-rdf-syntax-ns#type http://dbpedia.org/ontology/Work .
问题:同一部电影的所有类别都返回5次:Film,Thing,Q386724,WIKIdata:Q11424,而Work是等效的类(或存在子类关系) .
我的问题:
我希望三重回归
<http://dbpedia.org/resource/1001_Inventions_and_the_World_of_Ibn_Al-Haytham>
<http://www.w3.org/1999/02/22-rdf-syntax-ns#type>
<http://dbpedia.org/ontology/Film> .
并过滤掉其他4个三元组 .
怎么样?
先感谢您
2 回答
我认为以下内容适合您:
我想你想要这个查询