我知道这里有很多这样的错误,但这个查询似乎有所不同,因为它是一个插入查询 . 这是表card_info的架构:
CREATE TABLE card_info (
card_id mediumint(8) unsigned NOT NULL AUTO_INCREMENT,
card_name_orig varchar(150) NOT NULL,
card_name_html varchar(150) NOT NULL,
card_name_search varchar(150) NOT NULL,
card_name_page varchar(150) NOT NULL,
card_cost varchar(50) DEFAULT NULL,
card_cost_converted tinyint(2) NOT NULL DEFAULT '0',
card_subtype varchar(75) DEFAULT NULL,
card_oracle_text_orig text,
card_oracle_text_html text,
card_power varchar(10) DEFAULT NULL,
card_toughness varchar(10) DEFAULT NULL,
card_loyalty tinyint(1) DEFAULT NULL,
PRIMARY KEY (card_id),
KEY card_name_nd (card_name_search),
KEY card_name_page (card_name_page),
KEY card_cost_converted (card_cost_converted),
KEY card_power (card_power),
KEY card_toughness (card_toughness),
KEY card_loyalty (card_loyalty),
FULLTEXT KEY card_oracle_text_orig (card_oracle_text_orig),
FULLTEXT KEY card_name_search (card_name_search)
) ENGINE=MyISAM DEFAULT CHARSET=utf8
这是我的查询:
INSERT INTO card_info (
card_name_orig, card_name_html, card_name_search, card_name_page, card_cost,
card_cost_converted, card_subtype, card_oracle_text_orig, card_oracle_text_html,
card_power, card_toughness, card_loyalty
)
SELECT DISTINCT
d.name_orig, d.name_html, d.name_search, d.name_page, d.cost,
COALESCE(d.cost_converted, 0), d.type_sub, d.oracle_text_orig,
d.oracle_text_html, d.`power`, d.toughness, d.loyalty
FROM card_info_de d
LEFT OUTER JOIN card_info i ON d.name_search = i.card_name_search
WHERE i.card_id IS NULL
AND d.edition_id = 'isd'
ORDER BY (d.collector_number + 0), d.collector_number;
如果我执行此查询,我收到此错误:
1292 - 截断不正确的DOUBLE值:'181a'
请注意,值 181a 来自 card_info_de.collector_number 列,它是 VARCHAR(5) 字段,并且该字段无论如何都没有插入到 card_info 表中,它只是在select查询的order子句中使用 .
如果我仅从 SELECT
开始查询,我可以看到正在选择正确的结果,但是当我执行插入时,它会给出上面的错误 . 请注意,如果我从SELECT查询中删除ORDER BY子句,它会插入正常 . 我做错了 .
提前致谢 .
2 回答
我自己也遇到了同样的错误,这有点误导 . 我在另一个帖子中找到了答案:
Error Code 1292 - Truncated incorrect DOUBLE value - Mysql
所以基本上检查这些列中的任何一个被视为错误的数据类型:
d.name_search
i.card_name_search
d.edition_id
d.collector_number
尝试
ORDER BY(d.collector_number'0'),d.collector_number;
可怕如果是真的,但很有可能 .